Here is my HTML structure:
这是我的HTML结构:
<tr>
<td class="option_name_twitter">Something</td>
<td class="option_loading">
<img src="img/checked_successfully.png">
</td>
</tr>
<tr>
<td class="option_name_instagram">Something else</td>
<td class="option_loading">
<img src="img/checked_successfully.png">
</td>
</tr>
And here is my code:
这是我的代码:
$(document).on('click', "img[src$='checked_successfully.png']", function () {
var name = $(this).closest('td.option_loading').sibilings('td.^option_name_').attr('class');
})
I'm trying to get the last part of the classname's value of an element that starts with option_name_
. So the expected result is either twitter
or instagram
. How can I do that?
我正在尝试获取以option_name_开头的元素的classname值的最后一部分。所以预期的结果是推特或Instagram。我怎样才能做到这一点?
1 个解决方案
#1
5
You can achieve this by getting the class
from the sibling td
, splitting it in to an array using _
, then pop()
off the last element to get the value you need. Something like this:
您可以通过从兄弟td获取类,使用_将其拆分为数组,然后从最后一个元素中弹出()来获得所需的值来实现此目的。像这样的东西:
$(document).on('click', "img[src$='checked_successfully.png']", function() {
var name = $(this).closest('td.option_loading').prev('td').attr('class');
var site = name.split('_').pop();
console.log(site);
})
img {
border: 1px solid red;
width: 30px;
height: 30px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr>
<td class="option_name_twitter">Something</td>
<td class="option_loading">
<img src="img/checked_successfully.png">
</td>
</tr>
<tr>
<td class="option_name_instagram">Something else</td>
<td class="option_loading">
<img src="img/checked_successfully.png">
</td>
</tr>
</table>
You should however note that using the class
string in this way is not ideal, as it's very easily broken. Adding another class at the end of the attribute will break this code. A much better approach would be to store the value you need in its own data attribute - assuming you have access to edit the HTML.
但是你应该注意到以这种方式使用类字符串并不理想,因为它很容易被破坏。在属性末尾添加另一个类将破坏此代码。更好的方法是将所需的值存储在自己的数据属性中 - 假设您有权编辑HTML。
#1
5
You can achieve this by getting the class
from the sibling td
, splitting it in to an array using _
, then pop()
off the last element to get the value you need. Something like this:
您可以通过从兄弟td获取类,使用_将其拆分为数组,然后从最后一个元素中弹出()来获得所需的值来实现此目的。像这样的东西:
$(document).on('click', "img[src$='checked_successfully.png']", function() {
var name = $(this).closest('td.option_loading').prev('td').attr('class');
var site = name.split('_').pop();
console.log(site);
})
img {
border: 1px solid red;
width: 30px;
height: 30px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr>
<td class="option_name_twitter">Something</td>
<td class="option_loading">
<img src="img/checked_successfully.png">
</td>
</tr>
<tr>
<td class="option_name_instagram">Something else</td>
<td class="option_loading">
<img src="img/checked_successfully.png">
</td>
</tr>
</table>
You should however note that using the class
string in this way is not ideal, as it's very easily broken. Adding another class at the end of the attribute will break this code. A much better approach would be to store the value you need in its own data attribute - assuming you have access to edit the HTML.
但是你应该注意到以这种方式使用类字符串并不理想,因为它很容易被破坏。在属性末尾添加另一个类将破坏此代码。更好的方法是将所需的值存储在自己的数据属性中 - 假设您有权编辑HTML。