I want to get the name of the caller by the caller_id. Name is in the user table.
我想通过caller_id获取调用者的名字。名称位于用户表中。
Here's the migration file.
这是迁移文件。
class AddCallerIdToSeller < ActiveRecord::Migration
def change
add_column :users, :caller_id, :string
end
end
This is the view that I am currently doing.
这是我目前正在做的观点。
<td class="text-center"><%= call_report.caller_id.present? %></td>
When i do like above, it shows true. But I want to get the user name which is "=" caller_id
当我喜欢上面的时候,它表明了真实。但我想获得用户名为“=”caller_id
2 个解决方案
#1
1
User.find(call_report.caller_id).name
The best way to do this in the controller and assign it to some variable there.
在控制器中执行此操作并将其分配给某个变量的最佳方法。
#2
1
If you do this...
如果你这样做......
class CallReport < ApplicationRecord
belongs_to :user
end
You can then do
然后你可以做
call_report.user.name
Also the ID is normally stored as an integer, so it's more typical to see...
此外,ID通常存储为整数,因此更常见的是......
add_column :users, :caller_id, :integer
I'd do a rake db:rollback then make the above change then rake db:migrate
我做了一个rake db:rollback然后进行上面的更改然后rake db:migrate
#1
1
User.find(call_report.caller_id).name
The best way to do this in the controller and assign it to some variable there.
在控制器中执行此操作并将其分配给某个变量的最佳方法。
#2
1
If you do this...
如果你这样做......
class CallReport < ApplicationRecord
belongs_to :user
end
You can then do
然后你可以做
call_report.user.name
Also the ID is normally stored as an integer, so it's more typical to see...
此外,ID通常存储为整数,因此更常见的是......
add_column :users, :caller_id, :integer
I'd do a rake db:rollback then make the above change then rake db:migrate
我做了一个rake db:rollback然后进行上面的更改然后rake db:migrate