Could you tell me your way to delete an item from array? Do you think it's good?
你能告诉我怎么从数组中删除一个条目吗?你觉得这样好吗?
3 个解决方案
#1
9
That depends:
这取决于:
$a1 = array('a' => 1, 'b' => 2, 'c' => 3);
unset($a1['b']);
// array('a' => 1, 'c' => 3)
$a2 = array(1, 2, 3);
unset($a2[1]);
// array(0 => 1, 2 => 3)
// note the missing index 1
// solution 1 for numeric arrays
$a3 = array(1, 2, 3);
array_splice($a3, 1, 1);
// array(0 => 1, 1 => 3)
// index is now continous
// solution 2 for numeric arrays
$a4 = array(1, 2, 3);
unset($a4[1]);
$a4 = array_values($a4);
// array(0 => 1, 1 => 3)
// index is now continous
Generally unset()
is safe for hashtables (string-indexed arrays), but if you have to rely on continous numeric indexes you'll have to use either array_splice()
or a combination of unset()
and array_values()
.
一般来说,unset()对于散列表(字符串索引数组)是安全的,但是如果必须依赖连续的数字索引,则必须使用array_splice()或unset()和array_values()的组合。
#2
9
The common way:
常用方法:
According to the manual
根据手册
unset($arr[5]); // This removes the element from the array
The filtered way:
过滤的方法:
There is also the array_filter() function to take care of filtering arrays
还有array_filter()函数来处理过滤数组
$numeric_data = array_filter($data, "is_numeric");
To get a sequential index you can use
要获得一个可以使用的顺序索引
$numeric_data = array_values($numeric_data);
References
PHP – Delete selected items from an array
引用PHP -从数组中删除选定的项。
#3
5
It depends. If want to remove an element without causing gaps in the indexes, you need to use array_splice:
视情况而定。如果要删除一个元素而不造成索引中的空白,需要使用array_splice:
$a = array('a','b','c', 'd');
array_splice($a, 2, 1);
var_dump($a);
Output:
输出:
array(3) {
[0]=>
string(1) "a"
[1]=>
string(1) "b"
[2]=>
string(1) "d"
}
Using unset can work, but this results in a non-continuous index. This can sometimes be a problem when you iterate over the array using count($a) - 1 as a measure of the upper bound:
使用unset可以工作,但是这会导致一个非连续索引。当您使用count($a) - 1作为上界的度量来迭代数组时,这有时会成为一个问题:
$a = array('a','b','c', 'd');
unset($a[2]);
var_dump($a);
Output:
输出:
array(3) {
[0]=>
string(1) "a"
[1]=>
string(1) "b"
[3]=>
string(1) "d"
}
As you see, count is now 3 but the index of the last element is also 3.
如您所见,count现在是3,但是最后一个元素的索引也是3。
My recommendation is therefore to use array_splice for arrays with numerical indexes, and use unset only for arrays (dictionaries really) with non-numerical indexes.
因此,我建议对具有数值索引的数组使用array_splice,并只对具有非数值索引的数组(实际上是字典)使用unset。
#1
9
That depends:
这取决于:
$a1 = array('a' => 1, 'b' => 2, 'c' => 3);
unset($a1['b']);
// array('a' => 1, 'c' => 3)
$a2 = array(1, 2, 3);
unset($a2[1]);
// array(0 => 1, 2 => 3)
// note the missing index 1
// solution 1 for numeric arrays
$a3 = array(1, 2, 3);
array_splice($a3, 1, 1);
// array(0 => 1, 1 => 3)
// index is now continous
// solution 2 for numeric arrays
$a4 = array(1, 2, 3);
unset($a4[1]);
$a4 = array_values($a4);
// array(0 => 1, 1 => 3)
// index is now continous
Generally unset()
is safe for hashtables (string-indexed arrays), but if you have to rely on continous numeric indexes you'll have to use either array_splice()
or a combination of unset()
and array_values()
.
一般来说,unset()对于散列表(字符串索引数组)是安全的,但是如果必须依赖连续的数字索引,则必须使用array_splice()或unset()和array_values()的组合。
#2
9
The common way:
常用方法:
According to the manual
根据手册
unset($arr[5]); // This removes the element from the array
The filtered way:
过滤的方法:
There is also the array_filter() function to take care of filtering arrays
还有array_filter()函数来处理过滤数组
$numeric_data = array_filter($data, "is_numeric");
To get a sequential index you can use
要获得一个可以使用的顺序索引
$numeric_data = array_values($numeric_data);
References
PHP – Delete selected items from an array
引用PHP -从数组中删除选定的项。
#3
5
It depends. If want to remove an element without causing gaps in the indexes, you need to use array_splice:
视情况而定。如果要删除一个元素而不造成索引中的空白,需要使用array_splice:
$a = array('a','b','c', 'd');
array_splice($a, 2, 1);
var_dump($a);
Output:
输出:
array(3) {
[0]=>
string(1) "a"
[1]=>
string(1) "b"
[2]=>
string(1) "d"
}
Using unset can work, but this results in a non-continuous index. This can sometimes be a problem when you iterate over the array using count($a) - 1 as a measure of the upper bound:
使用unset可以工作,但是这会导致一个非连续索引。当您使用count($a) - 1作为上界的度量来迭代数组时,这有时会成为一个问题:
$a = array('a','b','c', 'd');
unset($a[2]);
var_dump($a);
Output:
输出:
array(3) {
[0]=>
string(1) "a"
[1]=>
string(1) "b"
[3]=>
string(1) "d"
}
As you see, count is now 3 but the index of the last element is also 3.
如您所见,count现在是3,但是最后一个元素的索引也是3。
My recommendation is therefore to use array_splice for arrays with numerical indexes, and use unset only for arrays (dictionaries really) with non-numerical indexes.
因此,我建议对具有数值索引的数组使用array_splice,并只对具有非数值索引的数组(实际上是字典)使用unset。