CodeIgniter ajax上传图片（ajax有效，不是CodeIgniter）

I do know how to upload an image by ajax in a traditional way. However, with the library upload from CodeIgniter I can't figure it out.

我知道如何以传统方式通过ajax上传图像。但是,从CodeIgniter上传库我无法弄明白。

But first, let me just tell you that I do not use a form at all.

但首先,让我告诉你,我根本不使用表格。

if(!empty($_FILES)){

    $this->load->helper('global_helper');

    $config['upload_path']   = base_url() + "public/images/";
    $config['file_name']     = randomName();
    $config['allowed_types'] = "jpg|png|bmp";
    $config['max_size']   = '500';
    $config['overwrite']      = FALSE;

    $this->load->library('upload', $config);

    if(!$this->upload->do_upload()){
        $error = array('error' => $this->upload->display_errors());
        print_r($error);
    }
}

This does not work because I'm receiving the following error:

这不起作用,因为我收到以下错误:

Array
(
    [error] => <p>You did not select a file to upload.</p>
)

But I actually did and it was actually uploaded to the server, because if I print out the $_FILES I receive:

但我实际上做了,它实际上传到服务器,因为如果我打印出我收到的$ _FILES:

Array
(
    [0] => Array
        (
            [name] => no_image.png
            [type] => image/png
            [tmp_name] => C:\xampp\tmp\php1715.tmp
            [error] => 0
            [size] => 6361
        )

)

Might be the problem of the input being in an Array(of Array[0])?

可能是输入在Array(Array [0])中的问题?

The javascript code is the following:

javascript代码如下:

event.stopPropagation();
event.preventDefault();
var data = new FormData();

if(picture != undefined){ 
    $.each(picture, function (key, value) {
        data.append(key, value);
    });
}

$.ajax({
    url: 'ajax_add',
    type: 'POST',
    data: data,
    cache: false,
    processData: false,  
    contentType: false, 
    success: function(aux){
        console.log(aux);
    }
});

I do not want to use the traditional way, but if I have too..

我不想用传统方式,但如果我也有...

Thanks.

1 个解决方案

#1

Not sure if it can work, because the file uploading class is designed to be used with a form, but you can try this

不确定它是否可以工作,因为文件上传类旨在与表单一起使用,但您可以尝试这样做

$this->upload->do_upload(0);

If it does what I think, it will select the first item of the $_FILES array. By default, it tries to find $_FILES['userfile'], who doesn't exists here (which is why you have the error).

如果它符合我的想法,它将选择$ _FILES数组的第一项。默认情况下,它会尝试查找$ _FILES ['userfile'],此处不存在(这就是您遇到错误的原因)。

Give it a try, and we'll see if it works :)

尝试一下,我们会看看它是否有效:)

#1