codeigniter表单使用ajax上传图片

I need to submit image with form data,I have search a better method for this, but unfortunately I couldn't find a better way for my purpose, previously done with this.serialize() method. But it doesn't work with images

我需要提交带有表单数据的图像，为此我搜索了一个更好的方法，但不幸的是，我找不到更好的方法来实现我的目的，之前我使用过this.serialize()方法。但它与图像无关。

here is my code

这是我的代码

view

视图

 <?php
          $this->load->helper('form');
          $attributes =  array('method'=>'post','name'=>'create_company','id'=>'create_company');
          echo form_open_multipart('',$attributes);?>
    <label>Code : </label> <?php echo form_input('code');?><br/><br/>
    <label>Name : </label> <?php echo form_input('name');?><br/><br/>
    <label>Logo : </label><input type="file" name="userfile"/><br/><br/>
    <label>URL : </label> <?php echo form_input('url');?><br/><br/>
    <label>Description : </label> <textarea name="description" rows="4" cols="50"> </textarea><br/><br/>
    <input type="submit" name="submit" value="Save"/>
    <?php echo form_close(); ?>     
</div>
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
    <script>//no need to specify the language
       $(document).ready(function() {

       $('#create_company').on("submit",function(e) {

            e.preventDefault();

            $.ajax({
                type: "POST",
                url: "<?php echo site_url('site/upload'); ?>",
                data: $(this).serialize(),
                success: function(data){
                    var site_url = "<?php echo site_url('site/create_branch_form'); ?>";
                    var json = $.parseJSON(data);
                    site_url = site_url +"/" + json.results[0].id ;
                    alert(site_url);
                    $("#content").load(site_url);
                    alert(data);
                }
           });            
        });
      });
    </script>

controller

控制器

public function upload(){

        //insert company details
    $this->load->model('company_model');
    $data['results'] = $this->company_model->insert_company();
    $this->output->set_output(json_encode($data));                
    }

model

模型

function insert_company(){
        //user details
        $username =  $this->session->userdata('username');
        //$query = $this->db->get_where('userdetails', array('username' => $username));

        $query =  $this->db->get_where('userdetails',array('username'=>$username));

        foreach ($query->result() as $function_info) 
        {
            $this->userid = $function_info->id;
        }

    $new_company_insert_data = array(

        'code' => $this->input->post('code'),
                    'name' => $this->input->post('name'),
                    'logo' => $imgpath['file_name'],
                    'url' => $this->input->post('url'),
                    'description' => $this->input->post('description'),
                    'createdat' => date('Y-m-d H:i:s',strtotime('')),
                    'status' => 0,
                    'userid' => $this->userid
             ); 

        $this->db->insert('companydetails',$new_company_insert_data);
        //get id of the last inserted row
        $this->load->database();
        $query = $this->db->query("SELECT MAX(id) AS id FROM companydetails");
        return $query->result();
}

3 个解决方案

#1

Try with FormData object. You should have something like this in your JS code :

尝试与FormData对象。在您的JS代码中应该有如下内容:

 $(document).ready(function() {

   $('#create_company').on("submit",function(e) {

        e.preventDefault();
        var formData = new FormData(this);

        $.ajax({
            type: "POST",
            url: "<?php echo site_url('site/upload'); ?>",
            data: formData,
            cache: false,
            contentType: false,
            processData: false
            success: function(data){
                //function success
            },
            error: function(data){
            //error function
        }
       });            
    });
  });

Hope this could help.

希望这可以帮助。

#2

Solution 1:

解决方案1:

Use FormData object for plain JQuery uploading.

使用FormData对象进行纯JQuery上传。

Check this link. It may not work in IE9 browser

检查这个链接。它可能在IE9浏览器中不起作用。

Solution 2:

解决方案2:

Use this uploader(there are many apart from this) for browser compatibility and more.

使用这个上传程序(除了这个之外还有很多)来实现浏览器兼容性和更多。

#3

Use jquery.form.js for upload form data with attachment. And add this function in controller.

使用jquery.form。js用于上传表单数据和附件。然后在控制器中添加这个函数。

function uploadFile($file, $uploads_dir, $allowfiles) {
        if ($file['size'] > 0) {
            $pic_name = "";
            $ext = pathinfo($file['name'], PATHINFO_EXTENSION);
            if (in_array($ext, $allowfiles)) {
                $pic_name = rand();
                $tmp_name = $file["tmp_name"];
                $pic_name.= $file["name"];
                move_uploaded_file($tmp_name, "$uploads_dir/$pic_name");
            }
            return $pic_name;
        } else {
            return "";
        }
    }

#1