How to pass form data using POST method and JS submit() ?
如何使用POST方法和JS submit()来传递表单数据?
I would like not to use AJAX.
我不想使用AJAX。
I can achieve that by using JS and GET method, but my goal now is to use JS (probably with submit() ) and POST method.
我可以通过使用JS和GET方法来实现这一点,但是我现在的目标是使用JS(可能是使用submit()和POST方法)。
Please give a simple working example.
请给出一个简单的工作示例。
Thank you!
谢谢你!
Edited: Sorry, I will be more specific. Here is a simple code I have:
编辑:不好意思,我再具体一点。这里有一个简单的代码:
<form name=\"myform\" action=\"\">
Search: <input type='text' name='query' />
<a href=\"javascript: submitform()\">Search</a>
</form>
<script type=\"text/javascript\">
function submitform() { document.myform.submit(); }
</script>
When I insert "word" into the input field and press Search, the URL becomes "../index.php?query=word" and that means that form data is passed like GET method.
当我在输入字段中插入“word”并按Search时,URL变为“../index.php?”查询=word",这意味着表单数据像GET方法一样被传递。
And my goal is to remove any form data from URL and pass it like with POST method.
我的目标是从URL中删除任何表单数据并像POST方法那样传递它。
Edited: ohh.. I just added method=post and no form data in the URL anymore :)
编辑:哦. .我只是添加了方法=post,在URL中没有表单数据:)
4 个解决方案
#1
8
Just have a form and submit it.
只要有一个表格,并提交它。
form = document.forms[0] //assuming only form.
form.submit();
EDIT: OP has clarified question
Specify a method
attribute on your form.
在窗体上指定方法属性。
<form name="myform" action="" method="POST">
It will cause the form to be submitted as a POST.
它将导致表单作为一个帖子提交。
#2
3
As mentioned already, you can use a form. I find it useful to have a function which creates a form on-the-fly and submits it - that way you don't need to clutter your markup with forms until they're needed by your JS.
如前所述,您可以使用表单。我发现,有一个动态创建表单并提交表单的函数非常有用——这样,在JS需要表单之前,您就不需要在标记中添加表单了。
function PostObjectToUri(uri, obj) {
"use strict";
var json, form, input;
json = JSON.stringify(obj);
form = document.createElement("form");
form.method = "post";
form.action = uri;
input = document.createElement("input");
input.setAttribute("name", "json");
input.setAttribute("value", json);
form.appendChild(input);
document.body.appendChild(form);
form.submit();
};
Obviously that example JSON-serializes an object into a string and sets it on a single input, but you could adapt it to do whatever you need.
显然,这个示例json将对象序列化为字符串,并将其设置为单个输入,但您可以对其进行调整,以完成所需的工作。
EDIT: I'm not actually sure whether you even need to append to the DOM before submitting - can anyone clarify?
编辑:我不确定你是否需要在提交之前添加到DOM -有人能澄清吗?
#3
3
Set the form's method
attribute to POST:
将表单的方法属性设置为POST:
<form method="post">
And then submit the form via JavaScript using <formelement>.submit()
然后使用
#4
0
jQuery AJAX post is best way to do it. See below example code.
jQuery AJAX post是最好的方法。看到下面的示例代码。
e.preventDefault();
$.ajax({
type: 'post',
url: 'data.php',
data: $('form').serialize(),
success: function(response) {
$('#DisplayDiv').html(response);
}
});
#1
8
Just have a form and submit it.
只要有一个表格,并提交它。
form = document.forms[0] //assuming only form.
form.submit();
EDIT: OP has clarified question
Specify a method
attribute on your form.
在窗体上指定方法属性。
<form name="myform" action="" method="POST">
It will cause the form to be submitted as a POST.
它将导致表单作为一个帖子提交。
#2
3
As mentioned already, you can use a form. I find it useful to have a function which creates a form on-the-fly and submits it - that way you don't need to clutter your markup with forms until they're needed by your JS.
如前所述,您可以使用表单。我发现,有一个动态创建表单并提交表单的函数非常有用——这样,在JS需要表单之前,您就不需要在标记中添加表单了。
function PostObjectToUri(uri, obj) {
"use strict";
var json, form, input;
json = JSON.stringify(obj);
form = document.createElement("form");
form.method = "post";
form.action = uri;
input = document.createElement("input");
input.setAttribute("name", "json");
input.setAttribute("value", json);
form.appendChild(input);
document.body.appendChild(form);
form.submit();
};
Obviously that example JSON-serializes an object into a string and sets it on a single input, but you could adapt it to do whatever you need.
显然,这个示例json将对象序列化为字符串,并将其设置为单个输入,但您可以对其进行调整,以完成所需的工作。
EDIT: I'm not actually sure whether you even need to append to the DOM before submitting - can anyone clarify?
编辑:我不确定你是否需要在提交之前添加到DOM -有人能澄清吗?
#3
3
Set the form's method
attribute to POST:
将表单的方法属性设置为POST:
<form method="post">
And then submit the form via JavaScript using <formelement>.submit()
然后使用
#4
0
jQuery AJAX post is best way to do it. See below example code.
jQuery AJAX post是最好的方法。看到下面的示例代码。
e.preventDefault();
$.ajax({
type: 'post',
url: 'data.php',
data: $('form').serialize(),
success: function(response) {
$('#DisplayDiv').html(response);
}
});