Here is the deal (using php and laravel-5.2).
I have some forms
in a page, and when i submit another form
not the first one then it keeps submit the first form
.
Here my html code:
这是交易(使用php和laravel-5.2)。我在页面中有一些表单,当我提交另一个表单而不是第一个表单时,它会继续提交第一个表单。这是我的HTML代码:
<form method="POST" action="http://localhost:8888/candidates/18" accept-charset="UTF-8" id="name-edit" style="display:none">
<input name="_method" type="hidden" value="PUT">
<input name="_token" type="hidden" value="xxzvu6HIqP8k2kg78pxuHiTc8NWftjNL1IJvxbDo">
<div class="form-group ">
<div class="col-xs-12 col-sm-5 ">
<input placeholder="Full Name" error="" id="name-input" class="width-100" name="name" type="text" value="chi qua uqaaa1232">
</div>
</div>
<button class="green btn-link col-xs-4" type="submit"><i class="ace-icon glyphicon glyphicon-ok"></i> Click to save or press Enter</button>
</form>
<form method="POST" action="http://localhost:8888/candidates/18" accept-charset="UTF-8" id="address-edit" style="display:none">
<input name="_method" type="hidden" value="PUT">
<input name="_token" type="hidden" value="xxzvu6HIqP8k2kg78pxuHiTc8NWftjNL1IJvxbDo">
<div class="form-group ">
<div class="col-xs-12 col-sm-5 ">
<input placeholder="Address" error="" id="address-input" class="width-100" name="address" type="text" value="nha xacdawdwad">
</div>
</div>
<button class="green btn-link col-xs-4" type="submit"><i class="ace-icon glyphicon glyphicon-ok"></i> Click to save or press Enter</button>
</form>
My jquery code for both forms:
我的两种形式的jquery代码:
$(document).ready(function(){
$("#name-edit").focusout(function() {
$('#name-edit').css('display', 'none');
$('#name-view').css('display', 'inline');
});
$("#address-edit").focusout(function() {
$('#address-edit').css('display', 'none');
$('#address-view').css('display', 'inline');
});
});
$('#btn-edit-name').click(function () {
var name = $('#name-view').css('display', 'none').clone().children().remove().end().text();
$('#name-input').val(name);
$('#name-edit').css('display', 'inline').focus();
});
$('#btn-edit-address').click(function () {
var name = $('#address-view').css('display', 'none').clone().children().remove().end().text();
$('#address-input').val(name);
$('#address-edit').css('display', 'inline').focus();
});
btn-edit-name
and btn-edit-address
for showing the form. thanks for your consider.
here is my UI:
用于显示表单的btn-edit-name和btn-edit-address。谢谢你的考虑。这是我的用户界面:
3 个解决方案
#1
1
You can't submit 2 forms simultaneously.
您不能同时提交2份表格。
Instead of having 2 forms for name and address fields you can add them into single form like below:
您可以将它们添加到单个表单中,而不是像名称和地址字段一样有两个表单:
<form method="POST" action="http://localhost:8888/candidates/18" accept-charset="UTF-8" id="name-edit" style="display:none">
<input name="_method" type="hidden" value="PUT">
<input name="_token" type="hidden" value="xxzvu6HIqP8k2kg78pxuHiTc8NWftjNL1IJvxbDo">
<div class="form-group ">
<div class="col-xs-12 col-sm-5 ">
<input placeholder="Full Name" error="" id="name-input" class="width-100" name="name" type="text" value="chi qua uqaaa1232">
</div>
</div>
<div class="form-group ">
<div class="col-xs-12 col-sm-5 ">
<input placeholder="Address" error="" id="address-input" class="width-100" name="address" type="text" value="nha xacdawdwad">
</div>
</div>
<button class="green btn-link col-xs-4" type="submit"><i class="ace-icon glyphicon glyphicon-ok"></i> Click to save or press Enter</button>
</form>
If you wish to show hide them on click then you can add some jQuery to do so.
如果你想显示隐藏它们点击然后你可以添加一些jQuery这样做。
#2
0
oh i found the answer that set the type
submit button to button
then make jquery
for click event $(this).closest('form').submit()
哦,我找到了答案,将类型提交按钮设置为按钮,然后为点击事件$(this).closest('form')生成jquery。submit()
#3
0
You can either have two different actions
您可以有两种不同的操作
action="http://localhost:8888/candidates/18"
action="http://localhost:8888/candidates/19"
If not possible add different hidden input to each form like
如果不可能,为每个表单添加不同的隐藏输入
In form 1 add this line
在表单1中添加此行
<input type="hidden" name="identifier" value="form1">
In form 2 add this line
在表单2中添加此行
<input type="hidden" name="identifier" value="form2">
Now you can either use if ($_POST['identifier'] == 'form1')
现在你可以使用if($ _POST ['identifier'] =='form1')
OR
You can use a switch statement also
您也可以使用switch语句
switch($_POST['identifier']){
case 'form1':{}
case 'form2':{}
}
Also your two submit buttons are identical. You can set a value for each that you can check after submission. Set value like this For form 1 name
您的两个提交按钮也是相同的。您可以为提交后可以检查的每个设置一个值。像这样设置值对于表单1的名称
<button class="green btn-link col-xs-4" type="submit" value="name" name="name"><i class="ace-icon glyphicon glyphicon-ok"></i> Click to save or press Enter</button>
For form 2 address
表格2地址
<button class="green btn-link col-xs-4" type="submit" value="address" name="address"><i class="ace-icon glyphicon glyphicon-ok"></i> Click to save or press Enter</button>
#1
1
You can't submit 2 forms simultaneously.
您不能同时提交2份表格。
Instead of having 2 forms for name and address fields you can add them into single form like below:
您可以将它们添加到单个表单中,而不是像名称和地址字段一样有两个表单:
<form method="POST" action="http://localhost:8888/candidates/18" accept-charset="UTF-8" id="name-edit" style="display:none">
<input name="_method" type="hidden" value="PUT">
<input name="_token" type="hidden" value="xxzvu6HIqP8k2kg78pxuHiTc8NWftjNL1IJvxbDo">
<div class="form-group ">
<div class="col-xs-12 col-sm-5 ">
<input placeholder="Full Name" error="" id="name-input" class="width-100" name="name" type="text" value="chi qua uqaaa1232">
</div>
</div>
<div class="form-group ">
<div class="col-xs-12 col-sm-5 ">
<input placeholder="Address" error="" id="address-input" class="width-100" name="address" type="text" value="nha xacdawdwad">
</div>
</div>
<button class="green btn-link col-xs-4" type="submit"><i class="ace-icon glyphicon glyphicon-ok"></i> Click to save or press Enter</button>
</form>
If you wish to show hide them on click then you can add some jQuery to do so.
如果你想显示隐藏它们点击然后你可以添加一些jQuery这样做。
#2
0
oh i found the answer that set the type
submit button to button
then make jquery
for click event $(this).closest('form').submit()
哦,我找到了答案,将类型提交按钮设置为按钮,然后为点击事件$(this).closest('form')生成jquery。submit()
#3
0
You can either have two different actions
您可以有两种不同的操作
action="http://localhost:8888/candidates/18"
action="http://localhost:8888/candidates/19"
If not possible add different hidden input to each form like
如果不可能,为每个表单添加不同的隐藏输入
In form 1 add this line
在表单1中添加此行
<input type="hidden" name="identifier" value="form1">
In form 2 add this line
在表单2中添加此行
<input type="hidden" name="identifier" value="form2">
Now you can either use if ($_POST['identifier'] == 'form1')
现在你可以使用if($ _POST ['identifier'] =='form1')
OR
You can use a switch statement also
您也可以使用switch语句
switch($_POST['identifier']){
case 'form1':{}
case 'form2':{}
}
Also your two submit buttons are identical. You can set a value for each that you can check after submission. Set value like this For form 1 name
您的两个提交按钮也是相同的。您可以为提交后可以检查的每个设置一个值。像这样设置值对于表单1的名称
<button class="green btn-link col-xs-4" type="submit" value="name" name="name"><i class="ace-icon glyphicon glyphicon-ok"></i> Click to save or press Enter</button>
For form 2 address
表格2地址
<button class="green btn-link col-xs-4" type="submit" value="address" name="address"><i class="ace-icon glyphicon glyphicon-ok"></i> Click to save or press Enter</button>