使用paramiko检查远程主机上是否存在路径

Paramiko's SFTPClient apparently does not have an exists method. This is my current implementation:

Paramiko的SFTPClient显然没有存在方法。这是我目前的实施:

def rexists(sftp, path):
    """os.path.exists for paramiko's SCP object
    """
    try:
        sftp.stat(path)
    except IOError, e:
        if 'No such file' in str(e):
            return False
        raise
    else:
        return True

Is there a better way to do this? Checking for substring in Exception messages is pretty ugly and can be unreliable.

有一个更好的方法吗?在异常消息中检查子字符串非常难看,并且可能不可靠。

2 个解决方案

#1

See the errno module for constants defining all those error codes. Also, it's a bit clearer to use the errno attribute of the exception than the expansion of the __init__ args, so I'd do this:

有关定义所有这些错误代码的常量,请参阅errno模块。此外,使用异常的errno属性比__init__ args的扩展更清楚,所以我这样做:

except IOError, e: # or "as" if you're using Python 3.0
  if e.errno == errno.ENOENT:
    ...

#2

There is no "exists" method defined for SFTP (not just paramiko), so your method is fine.

没有为SFTP(不仅仅是paramiko)定义“存在”方法,所以你的方法很好。

I think checking the errno is a little cleaner:

我认为检查errno有点清洁:

def rexists(sftp, path):
    """os.path.exists for paramiko's SCP object
    """
    try:
        sftp.stat(path)
    except IOError, e:
        if e[0] == 2:
            return False
        raise
    else:
        return True

#1