未激活时链接到类

时间:2022-11-21 15:23:19

I have a link to helper that generate a <span>. The <span> should:

我有一个生成的帮助器链接。 应该:

  1. have the class:"arrow open" when it is active.
  2. 有活动的类:“箭头打开”。
  3. have the class:"arrow" when it is NOT active.

    当它不活动时,使用类:“箭头”。

    {{#link-to 'status' tagName="span" activeClass="arrow open"}} {{/link-to}}

    {{#link-to'status'tagName =“span”activeClass =“arrow open”}} {{/ link-to}}

Question: The point 1 is working with the use of the activeClass. However, I don't how to assign a class when the link-to helper is not active as per the point 2.

问题:第1点正在使用activeClass。但是,当链接到帮助程序未按照第2点激活时,我不知道如何分配类。

tks

TKS

1 个解决方案

#1


1  

Adapted from the guides:

改编自指南:

{{#link-to 'status' tagName='span' class='arrow' activeClass='open'}} {{/link-to}}

The class property lets you set the class that will be present at all times.

class属性允许您设置将始终存在的类。

#1


1  

Adapted from the guides:

改编自指南:

{{#link-to 'status' tagName='span' class='arrow' activeClass='open'}} {{/link-to}}

The class property lets you set the class that will be present at all times.

class属性允许您设置将始终存在的类。