UVaLive 6608 Cabin Baggage (水题)

时间：2023-12-22 18:25:14

题意：给定四个数代表长宽高和重，问你是不是满足下面条件，长不高于56，宽不宽于45，高不高于25，或者总和不大于125，并且重量不高于7.

析：判断输出就好，注意这个题是或，不要想错了。

代码如下：

#pragma comment(linker, "/STACK:1024000000,1024000000")

#include <cstdio>

#include <string>

#include <cstdlib>

#include <cmath>

#include <iostream>

#include <cstring>

#include <set>

#include <queue>

#include <algorithm>

#include <vector>

#include <map>

#include <cctype>

#include <cmath>

#include <stack>

#include <sstream>

#define frer freopen("in.txt", "r", stdin)

#define frew freopen("out.txt", "w", stdout)

using namespace std;

typedef long long LL;

typedef pair<int, int> P;

const int INF = 0x3f3f3f3f;

const double inf = 0x3f3f3f3f3f3f;

const double PI = acos(-1.0);

const double eps = 1e-8;

const int maxn = 1e3 + 5;

const int mod = 1e9 + 7;

const char *mark = "+-*";

const int dr[] = {1, 0, -1, 0};

const int dc[] = {0, 1, 0, -1};

const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};

int n, m;

const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

inline int Min(int a, int b){ return a < b ? a : b; }

inline int Max(int a, int b){ return a > b ? a : b; }

inline LL Min(LL a, LL b){ return a < b ? a : b; }

inline LL Max(LL a, LL b){ return a > b ? a : b; }

inline bool is_in(int r, int c){

    return r >= 0 && r < n && c >= 0 && c < m;

}

int main(){

    int T;  cin >> T;

    int ans = 0;

    while(T--){

        double a, b, c, d;

        cin >> a >> b >> c >> d;

        double e = a + b + c;

        if(d  <= 7.0 && (e <= 125.0 || a <= 56 && b <= 45 && c <= 25)) {  printf("1\n");  ++ans; }

        else  printf("0\n");

    }

    printf("%d\n", ans);

    return 0;

}

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