I've a Drawable xml file (background.xml):
我有一个Drawable xml文件(background.xml):
<?xml version="1.0" encoding="UTF-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item>
<shape>
...........
</shape>
</item>
<item android:id="@+id/shape_id">
<shape android:shape="rectangle">
<solid android:color="#ffefefef" />
</shape>
</item>
</layer-list>
used by a LinearLayout:
由LinearLayout使用:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:background="@drawable/background"
android:id="@+id/layout_id"
>
Now i need to change the shape shape_id
solid color at runtime based on some conditions. How to do this?
现在我需要在运行时根据某些条件更改shape_id纯色。这个怎么做?
1 个解决方案
#1
60
Found by me:
发现我:
View v = findViewById(R.id.layout_id);
LayerDrawable bgDrawable = (LayerDrawable)v.getBackground();
final GradientDrawable shape = (GradientDrawable) bgDrawable.findDrawableByLayerId(R.id.shape_id);
shape.setColor(----);
#1
60
Found by me:
发现我:
View v = findViewById(R.id.layout_id);
LayerDrawable bgDrawable = (LayerDrawable)v.getBackground();
final GradientDrawable shape = (GradientDrawable) bgDrawable.findDrawableByLayerId(R.id.shape_id);
shape.setColor(----);