How can I generate the following XML using JAXB?
如何使用JAXB生成以下XML ?
<sport type="" gender="">
sport description
</sport>
4 个解决方案
#1
103
Annotate type and gender properties with @XmlAttribute
and the description property with @XmlValue
:
使用@XmlAttribute注释类型和性别属性,使用@XmlValue注释描述属性:
package org.example.sport;
import javax.xml.bind.annotation.*;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement
public class Sport {
@XmlAttribute
protected String type;
@XmlAttribute
protected String gender;
@XmlValue;
protected String description;
}
For More Information
的更多信息
- http://bdoughan.blogspot.com/2011/06/jaxb-and-complex-types-with-simple.html
- http://bdoughan.blogspot.com/2011/06/jaxb-and-complex-types-with-simple.html
#2
7
The correct scheme should be:
正确的方案应该是:
<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.example.org/Sport"
xmlns:tns="http://www.example.org/Sport"
elementFormDefault="qualified"
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
jaxb:version="2.0">
<complexType name="sportType">
<simpleContent>
<extension base="string">
<attribute name="type" type="string" />
<attribute name="gender" type="string" />
</extension>
</simpleContent>
</complexType>
<element name="sports">
<complexType>
<sequence>
<element name="sport" minOccurs="0" maxOccurs="unbounded"
type="tns:sportType" />
</sequence>
</complexType>
</element>
Code generated for SportType will be:
为SportType生成的代码如下:
package org.example.sport;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "sportType")
public class SportType {
@XmlValue
protected String value;
@XmlAttribute
protected String type;
@XmlAttribute
protected String gender;
public String getValue() {
return value;
}
public void setValue(String value) {
this.value = value;
}
public String getType() {
return type;
}
public void setType(String value) {
this.type = value;
}
public String getGender() {
return gender;
}
public void setGender(String value) {
this.gender = value;
}
}
#3
5
Updated Solution - using the schema solution that we were debating. This gets you to your answer:
更新的解决方案——使用我们正在讨论的模式解决方案。这让你得到了答案:
Sample Schema:
示例模式:
<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.example.org/Sport"
xmlns:tns="http://www.example.org/Sport"
elementFormDefault="qualified"
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
jaxb:version="2.0">
<complexType name="sportType">
<attribute name="type" type="string" />
<attribute name="gender" type="string" />
</complexType>
<element name="sports">
<complexType>
<sequence>
<element name="sport" minOccurs="0" maxOccurs="unbounded"
type="tns:sportType" />
</sequence>
</complexType>
</element>
Code Generated
生成的代码
SportType:
SportType:
package org.example.sport;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "sportType")
public class SportType {
@XmlAttribute
protected String type;
@XmlAttribute
protected String gender;
public String getType() {
return type;
}
public void setType(String value) {
this.type = value;
}
public String getGender() {
return gender;
}
public void setGender(String value) {
this.gender = value;
}
}
Sports:
运动:
package org.example.sport;
import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
"sport"
})
@XmlRootElement(name = "sports")
public class Sports {
protected List<SportType> sport;
public List<SportType> getSport() {
if (sport == null) {
sport = new ArrayList<SportType>();
}
return this.sport;
}
}
Output class files are produced by running xjc against the schema on the command line
输出类文件是通过对命令行上的模式运行xjc生成的
#4
4
Here is working solution:
这是工作的解决方案:
Output:
输出:
public class XmlTest {
private static final Logger log = LoggerFactory.getLogger(XmlTest.class);
@Test
public void createDefaultBook() throws JAXBException {
JAXBContext jaxbContext = JAXBContext.newInstance(Book.class);
Marshaller marshaller = jaxbContext.createMarshaller();
StringWriter writer = new StringWriter();
marshaller.marshal(new Book(), writer);
log.debug("Book xml:\n {}", writer.toString());
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "book")
public static class Book {
@XmlElementRef(name = "price")
private Price price = new Price();
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "price")
public static class Price {
@XmlAttribute(name = "drawable")
private Boolean drawable = true; //you may want to set default value here
@XmlValue
private int priceValue = 1234;
public Boolean getDrawable() {
return drawable;
}
public void setDrawable(Boolean drawable) {
this.drawable = drawable;
}
public int getPriceValue() {
return priceValue;
}
public void setPriceValue(int priceValue) {
this.priceValue = priceValue;
}
}
}
Output:
输出:
22:00:18.471 [main] DEBUG com.grebski.stack.XmlTest - Book xml:
22:00:18.471[主要]调试com.grebski.stack。使用xmlt册xml:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<book>
<price drawable="true">1234</price>
</book>
#1
103
Annotate type and gender properties with @XmlAttribute
and the description property with @XmlValue
:
使用@XmlAttribute注释类型和性别属性,使用@XmlValue注释描述属性:
package org.example.sport;
import javax.xml.bind.annotation.*;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement
public class Sport {
@XmlAttribute
protected String type;
@XmlAttribute
protected String gender;
@XmlValue;
protected String description;
}
For More Information
的更多信息
- http://bdoughan.blogspot.com/2011/06/jaxb-and-complex-types-with-simple.html
- http://bdoughan.blogspot.com/2011/06/jaxb-and-complex-types-with-simple.html
#2
7
The correct scheme should be:
正确的方案应该是:
<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.example.org/Sport"
xmlns:tns="http://www.example.org/Sport"
elementFormDefault="qualified"
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
jaxb:version="2.0">
<complexType name="sportType">
<simpleContent>
<extension base="string">
<attribute name="type" type="string" />
<attribute name="gender" type="string" />
</extension>
</simpleContent>
</complexType>
<element name="sports">
<complexType>
<sequence>
<element name="sport" minOccurs="0" maxOccurs="unbounded"
type="tns:sportType" />
</sequence>
</complexType>
</element>
Code generated for SportType will be:
为SportType生成的代码如下:
package org.example.sport;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "sportType")
public class SportType {
@XmlValue
protected String value;
@XmlAttribute
protected String type;
@XmlAttribute
protected String gender;
public String getValue() {
return value;
}
public void setValue(String value) {
this.value = value;
}
public String getType() {
return type;
}
public void setType(String value) {
this.type = value;
}
public String getGender() {
return gender;
}
public void setGender(String value) {
this.gender = value;
}
}
#3
5
Updated Solution - using the schema solution that we were debating. This gets you to your answer:
更新的解决方案——使用我们正在讨论的模式解决方案。这让你得到了答案:
Sample Schema:
示例模式:
<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.example.org/Sport"
xmlns:tns="http://www.example.org/Sport"
elementFormDefault="qualified"
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
jaxb:version="2.0">
<complexType name="sportType">
<attribute name="type" type="string" />
<attribute name="gender" type="string" />
</complexType>
<element name="sports">
<complexType>
<sequence>
<element name="sport" minOccurs="0" maxOccurs="unbounded"
type="tns:sportType" />
</sequence>
</complexType>
</element>
Code Generated
生成的代码
SportType:
SportType:
package org.example.sport;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "sportType")
public class SportType {
@XmlAttribute
protected String type;
@XmlAttribute
protected String gender;
public String getType() {
return type;
}
public void setType(String value) {
this.type = value;
}
public String getGender() {
return gender;
}
public void setGender(String value) {
this.gender = value;
}
}
Sports:
运动:
package org.example.sport;
import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
"sport"
})
@XmlRootElement(name = "sports")
public class Sports {
protected List<SportType> sport;
public List<SportType> getSport() {
if (sport == null) {
sport = new ArrayList<SportType>();
}
return this.sport;
}
}
Output class files are produced by running xjc against the schema on the command line
输出类文件是通过对命令行上的模式运行xjc生成的
#4
4
Here is working solution:
这是工作的解决方案:
Output:
输出:
public class XmlTest {
private static final Logger log = LoggerFactory.getLogger(XmlTest.class);
@Test
public void createDefaultBook() throws JAXBException {
JAXBContext jaxbContext = JAXBContext.newInstance(Book.class);
Marshaller marshaller = jaxbContext.createMarshaller();
StringWriter writer = new StringWriter();
marshaller.marshal(new Book(), writer);
log.debug("Book xml:\n {}", writer.toString());
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "book")
public static class Book {
@XmlElementRef(name = "price")
private Price price = new Price();
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "price")
public static class Price {
@XmlAttribute(name = "drawable")
private Boolean drawable = true; //you may want to set default value here
@XmlValue
private int priceValue = 1234;
public Boolean getDrawable() {
return drawable;
}
public void setDrawable(Boolean drawable) {
this.drawable = drawable;
}
public int getPriceValue() {
return priceValue;
}
public void setPriceValue(int priceValue) {
this.priceValue = priceValue;
}
}
}
Output:
输出:
22:00:18.471 [main] DEBUG com.grebski.stack.XmlTest - Book xml:
22:00:18.471[主要]调试com.grebski.stack。使用xmlt册xml:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<book>
<price drawable="true">1234</price>
</book>