本文实例讲述了Python实现的根据文件名查找数据文件功能。分享给大家供大家参考,具体如下:
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#-*- coding: UTF-8 -*-
import os
import shutil
AllFiles = []
NameFiles = []
def findFie(filePath):
pathDir = os.listdir(filePath)
for allDir in pathDir:
# print(allDir)
AllFiles.append(allDir)
#pass
#filepath = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71\\71sns'
#copyfile = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71mtp'
filepath = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72\\72sns'
copyfile = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72mtp'
shutil.rmtree(copyfile)
os.mkdir(copyfile)
findFie(filepath)
def readFile():
readFile = open ( './jobname' )
i = 0
for eachLine in readFile:
i = i + 1
#print(eachLine)
NameFiles.append(eachLine.replace( '\n' ,'')) # 去掉换行符
readFile()
#字符串比较
def doTheCompare():
for x in NameFiles:
print (x)
for y in AllFiles:
if x = = y :
copyFrom = os.path.join(filepath,x)
copyTo = os.path.join(copyfile,x)
shutil.copyfile(copyFrom,copyTo)
else :
pass
#print ("file not find under sns process,thanks .please check with wumi.")
doTheCompare()
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附:这里再补充一个更为简单的文件搜索功能示例:
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# -*- coding:utf-8 -*-
import os
def search(path = "." , name = "1" ):
for item in os.listdir(path):
item_path = os.path.join(path, item)
if os.path.isdir(item_path):
search(item_path, name)
elif os.path.isfile(item_path):
if name in item:
print (item_path)
if __name__ = = "__main__" :
search(path = r "D:\360Downloads" ,name = "dll" )
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希望本文所述对大家Python程序设计有所帮助。
原文链接:https://blog.csdn.net/haohaixingyun/article/details/77897338