I have some problems with a jQuery selector.
我有一个jQuery选择器的问题。
Let's say I have the following html where (...)
stands for an undefined number of html tags.
假设我有以下html,其中(...)代表未定义数量的html标签。
(...)
<div class="container">
(...)
<div class="subContainer">
(...)
<div class="container">
(...)
<div class="subContainer"/>
(...)
</div>
(...)
</div>
(...)
</div>
(...)
Let say that I have a javascript variable called container
that points to the first div (with class container). I want a jquery that selects the first subcontainer but not the nested one. If I use$(".subContainer", container);
I'll get both of them.
假设我有一个名为container的javascript变量,它指向第一个div(带有类容器)。我想要一个jquery来选择第一个子容器而不是嵌套的子容器。如果我使用$(“。subContainer”,容器);我会得到他们两个。
I've tried using
我试过用过
$(".subContainer:not(.container .subContainer)", container);
but this returns an empty set. Any solution?
但这会返回一个空集。有解决方案吗
Thanks.
谢谢。
4 个解决方案
#1
7
You can use direct child
selector:
您可以使用直接子选择器:
$("> .subContainer", container);
If container
is a jQuery object that refers to top-level .container
element you can also use children
method:
如果container是引用*.container元素的jQuery对象,您还可以使用children方法:
container.children('.subContainer');
Or find
and first
methods:
或者找到第一种方法:
container.find('.subContainer').first();
#2
7
Based on Jquery: Get all elements of a class that are not decendents of an element with the same class name? I've developed the following solution. Thanks to all.
基于Jquery:获取一个类的所有元素,这些元素不是具有相同类名的元素的后代?我开发了以下解决方案。谢谢大家。
$.fn.findButNotNested = function(selector, notInSelector) {
var origElement = $(this);
return origElement.find(selector).filter(function() {
return origElement[0] == $(this).closest(notInSelector)[0];
});
};
#3
0
To get the first subContainer you can use
要获得第一个subContainer,您可以使用
$('.subContainer')[0]
#4
0
This seems to work for my own uses...
这似乎适用于我自己的用途......
$('.item').filter(function() { return $(this).parents('.item').length == 0; });
This returns only the #outer
div.
这只返回#outer div。
<div class="item" id="outer">
<div class="item" id="inner"></div>
</div>
#1
7
You can use direct child
selector:
您可以使用直接子选择器:
$("> .subContainer", container);
If container
is a jQuery object that refers to top-level .container
element you can also use children
method:
如果container是引用*.container元素的jQuery对象,您还可以使用children方法:
container.children('.subContainer');
Or find
and first
methods:
或者找到第一种方法:
container.find('.subContainer').first();
#2
7
Based on Jquery: Get all elements of a class that are not decendents of an element with the same class name? I've developed the following solution. Thanks to all.
基于Jquery:获取一个类的所有元素,这些元素不是具有相同类名的元素的后代?我开发了以下解决方案。谢谢大家。
$.fn.findButNotNested = function(selector, notInSelector) {
var origElement = $(this);
return origElement.find(selector).filter(function() {
return origElement[0] == $(this).closest(notInSelector)[0];
});
};
#3
0
To get the first subContainer you can use
要获得第一个subContainer,您可以使用
$('.subContainer')[0]
#4
0
This seems to work for my own uses...
这似乎适用于我自己的用途......
$('.item').filter(function() { return $(this).parents('.item').length == 0; });
This returns only the #outer
div.
这只返回#outer div。
<div class="item" id="outer">
<div class="item" id="inner"></div>
</div>