Dim striniData As String = "a b c d"
Dim sectionList As System.Text.RegularExpressions.MatchCollection
Try
'' Using regular expression to get all section names.
reg = New Regex(":%s/*//g")
sectionList = reg.Matches(striniData)
MsgBox(sectionList.count)
Catch ex As Exception
Throw ex
End Try
程序不报错,当没有结果。请指教一下。辛苦了。
8 个解决方案
#1
New Regex("[\x20 ]", g)
更多语法,推荐参考:
http://www.regexlab.com/zh/regref.htm
更多语法,推荐参考:
http://www.regexlab.com/zh/regref.htm
#2
New Regex("[\x20 ]", g)
能不能写个例子啊。我不是很明白,,辛苦了。
能不能写个例子啊。我不是很明白,,辛苦了。
#3
reg = New Regex("[\x20 ]{2,}");
striniData = reg.Replace(striniData, " ");
--- 或者 ---
striniData = Regex.Replace(striniData, "[\x20 ]{2,}", " ");
正则表达式语法帮助,参见:
http://www.regexlab.com/zh/regref.htm
striniData = reg.Replace(striniData, " ");
--- 或者 ---
striniData = Regex.Replace(striniData, "[\x20 ]{2,}", " ");
正则表达式语法帮助,参见:
http://www.regexlab.com/zh/regref.htm
#4
简单点:
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
.......
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
.......
#5
我有个笨办法, 写个死循环,如果有两个空格就换成一个空格,直到不再有2个空格。那也就只剩下一个空格了。
#6
string msg="1 2 3 4 5 6"
msg=Regex.Replace (msg, " +"," ");
结果:
msg=="1 2 3 4 5 6"
msg=Regex.Replace (msg, " +"," ");
结果:
msg=="1 2 3 4 5 6"
#7
sz_lgp(longguoping) 有点不智能,但这个方法很好
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
#8
string msg="1 2 3 4 5 6"
msg=Regex.Replace (msg, " +"," ");
结果:
msg=="1 2 3 4 5 6"
没测试,但是msg会不会 = “1+2+3++4+5+++6”啊
msg=Regex.Replace (msg, " +"," ");
结果:
msg=="1 2 3 4 5 6"
没测试,但是msg会不会 = “1+2+3++4+5+++6”啊
#1
New Regex("[\x20 ]", g)
更多语法,推荐参考:
http://www.regexlab.com/zh/regref.htm
更多语法,推荐参考:
http://www.regexlab.com/zh/regref.htm
#2
New Regex("[\x20 ]", g)
能不能写个例子啊。我不是很明白,,辛苦了。
能不能写个例子啊。我不是很明白,,辛苦了。
#3
reg = New Regex("[\x20 ]{2,}");
striniData = reg.Replace(striniData, " ");
--- 或者 ---
striniData = Regex.Replace(striniData, "[\x20 ]{2,}", " ");
正则表达式语法帮助,参见:
http://www.regexlab.com/zh/regref.htm
striniData = reg.Replace(striniData, " ");
--- 或者 ---
striniData = Regex.Replace(striniData, "[\x20 ]{2,}", " ");
正则表达式语法帮助,参见:
http://www.regexlab.com/zh/regref.htm
#4
简单点:
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
.......
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
.......
#5
我有个笨办法, 写个死循环,如果有两个空格就换成一个空格,直到不再有2个空格。那也就只剩下一个空格了。
#6
string msg="1 2 3 4 5 6"
msg=Regex.Replace (msg, " +"," ");
结果:
msg=="1 2 3 4 5 6"
msg=Regex.Replace (msg, " +"," ");
结果:
msg=="1 2 3 4 5 6"
#7
sz_lgp(longguoping) 有点不智能,但这个方法很好
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
string_xx=string_xx.replace(" "," ")
#8
string msg="1 2 3 4 5 6"
msg=Regex.Replace (msg, " +"," ");
结果:
msg=="1 2 3 4 5 6"
没测试,但是msg会不会 = “1+2+3++4+5+++6”啊
msg=Regex.Replace (msg, " +"," ");
结果:
msg=="1 2 3 4 5 6"
没测试,但是msg会不会 = “1+2+3++4+5+++6”啊