两天之间的Javascript天计算[重复]

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这个问题在这里已有答案：

Why this operation with date (number of days between 2 dates) return this value? 3 answers
为什么这个带日期的操作（两个日期之间的天数）会返回这个值？ 3个答案

var oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds
var firstDate = new Date(2013, 06, 30);
var secondDate = new Date(2013, 07, 01);
var diffDays = Math.round(Math.abs((secondDate.getTime() - firstDate.getTime()) / (oneDay)));

I run the above code the answer should be 1day. But It is giving me 2days. Can you help me?

我运行上面的代码答案应该是1天。但它给了我2天。你可以帮我吗？

2 个解决方案

#1

That's because months are 0 indexed in JavaScript. So your first date is in July, and the second one in August.

这是因为在JavaScript中索引的月数为0。所以你的第一次约会是在七月份，第二次是在八月份。

You're comparing with a month having 31 days, hence the correct difference of 2 days.

您与31天的月份进行比较，因此正确的差异为2天。

When I enter dates this way in JavaScript, I explicitly add the offset so that other coders don't read it wrong, it's too easy to make this error :

当我在JavaScript中以这种方式输入日期时，我明确地添加了偏移量，以便其他编码器不会读错，这很容易造成这个错误：

var firstDate = new Date(2013, 06 - 1, 30); // -1 due to the months being 0-indexed in JavaScript
var secondDate = new Date(2013, 07 - 1, 01);

Yes I had had my code "fixed"...

是的，我的代码“已修复”......

#2

In javascript month is starting from 00-Jan since 05-june

在javascript月份从05年1月1日开始

var oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds
var firstDate = new Date(2013, 05, 30);
var secondDate = new Date(2013, 06, 01);
var diffDays = (secondDate- firstDate)/oneDay;
alert(diffDays);

To avoid confusion you can use like the following

为避免混淆，您可以像下面这样使用

var oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds
var firstDate = new Date('JUNE 30,2013');
var secondDate = new Date('JULY 01,2013');
var diffDays = (secondDate- firstDate)/oneDay;
alert(diffDays);

#1