Given that I have two ES6 classes.
鉴于我有两个ES6课程。
This is class A:
这是A类:
import B from 'B';
class A {
someFunction(){
var dependency = new B();
dependency.doSomething();
}
}
And class B:
和B级:
class B{
doSomething(){
// does something
}
}
I am unit testing using mocha (with babel for ES6), chai and sinon, which works really great. But how can I provide a mock class for class B when testing class A?
我是使用mocha进行单元测试(使用babel for ES6),chai和sinon,它的效果非常好。但是,在测试A类时,如何为B类提供模拟类?
I want to mock the entire class B (or the needed function, doesn't actually matter) so that class A doesn't execute real code but I can provide testing functionality.
我想模拟整个类B(或所需的函数,实际上并不重要),以便A类不执行实际代码,但我可以提供测试功能。
This is, what the mocha test looks like for now:
这就是现在的mocha测试:
var A = require('path/to/A.js');
describe("Class A", () => {
var InstanceOfA;
beforeEach(() => {
InstanceOfA = new A();
});
it('should call B', () => {
InstanceOfA.someFunction();
// How to test A.someFunction() without relying on B???
});
});
1 个解决方案
#1
25
You can use SinonJS to create a stub to prevent the real function to be executed.
您可以使用SinonJS创建存根以防止执行实际功能。
For example, given class A:
例如,给定A类:
import B from './b';
class A {
someFunction(){
var dependency = new B();
return dependency.doSomething();
}
}
export default A;
And class B:
和B级:
class B {
doSomething(){
return 'real';
}
}
export default B;
The test could look like:
测试看起来像:
describe("Class A", () => {
var InstanceOfA;
beforeEach(() => {
InstanceOfA = new A();
});
it('should call B', () => {
sinon.stub(B.prototype, 'doSomething', () => 'mock');
let res = InstanceOfA.someFunction();
sinon.assert.calledOnce(B.prototype.doSomething);
res.should.equal('mock');
});
});
You can then restore the function if necessary using object.method.restore();
:
然后,您可以使用object.method.restore();在必要时恢复该功能:
var stub = sinon.stub(object, "method");
Replaces object.method with a stub function. The original function can be restored by callingobject.method.restore();
(orstub.restore();
). An exception is thrown if the property is not already a function, to help avoid typos when stubbing methods.var stub = sinon.stub(object,“method”);用stub函数替换object.method。可以通过调用object.method.restore()来恢复原始函数; (或stub.restore();)。如果属性不是函数,则抛出异常,以帮助避免在存根方法时出现拼写错误。
#1
25
You can use SinonJS to create a stub to prevent the real function to be executed.
您可以使用SinonJS创建存根以防止执行实际功能。
For example, given class A:
例如,给定A类:
import B from './b';
class A {
someFunction(){
var dependency = new B();
return dependency.doSomething();
}
}
export default A;
And class B:
和B级:
class B {
doSomething(){
return 'real';
}
}
export default B;
The test could look like:
测试看起来像:
describe("Class A", () => {
var InstanceOfA;
beforeEach(() => {
InstanceOfA = new A();
});
it('should call B', () => {
sinon.stub(B.prototype, 'doSomething', () => 'mock');
let res = InstanceOfA.someFunction();
sinon.assert.calledOnce(B.prototype.doSomething);
res.should.equal('mock');
});
});
You can then restore the function if necessary using object.method.restore();
:
然后,您可以使用object.method.restore();在必要时恢复该功能:
var stub = sinon.stub(object, "method");
Replaces object.method with a stub function. The original function can be restored by callingobject.method.restore();
(orstub.restore();
). An exception is thrown if the property is not already a function, to help avoid typos when stubbing methods.var stub = sinon.stub(object,“method”);用stub函数替换object.method。可以通过调用object.method.restore()来恢复原始函数; (或stub.restore();)。如果属性不是函数,则抛出异常,以帮助避免在存根方法时出现拼写错误。