转自:http://www.cnblogs.com/losesea/archive/2013/06/14/3134900.html
题目:有以下2个二维数组
1
$a=Array(0 => Array(id => 66,class_name => www.iiwnet.com),1 => Array(id => 67,class_name => linux ));
2
$b=Array(0 => Array(class_count=> 8),1 => Array(class_count => 2));
两个数组内容如上,如何把$a和$b合并成为一个新的二维数组,要求新数组内容如下:
1
Array(0 => Array(id => 66,class_name => www.iiwnet.com,class_count=> 8),1 => Array(id => 67,class_name => linux ,class_count => 2));
这个题目一定有人遇到过 正好今天群里有人问 就给出2种解法
以下代码由 PHP教程网 原创提供
01
方法一:
02
03
function arrpreg(){
04
$a=Array(0 => Array(id => 66,class_name => www.iiwnet.com),1 => Array(id => 67,class_name => linux ));
05
$b=Array(0 => Array(class_count=> 8),1 => Array(class_count => 2));
06
$arr = array();
07
foreach ($a as $k => $r) {
08
foreach($r as $k1 => $r1){
09
$arr[$k][$k1] = $r1;
10
}
11
}
12
foreach ($b as $k => $r) {
13
foreach($r as $k1 => $r1){
14
$arr[$k][$k1] = $r1;
15
}
16
}
17
return $arr;
18
}
19
$ar= arrpreg();
20
echo '<pre>';
21
print_r($ar);
22
echo '</pre>';
23
?>
24
25
方法二:
26
27
$a = array(0 => Array(id => 66,class_name => www.iiwnet.com),1 => Array(id => 67,class_name => linux ));
28
$b = array(0 => Array(class_count=> 8),1 => Array(class_count => 2));
29
$arr = array();
30
foreach($a as $k=>$r){
31
$arr[] = array_merge($r,$b[$k]);
32
}
33
echo '<pre>';
34
print_r($arr);
35
echo '</pre>';
转自http://www.2cto.com/kf/201210/159324.html
PHP二维数组合并,根据某个key合并
最终解决方案:
- /**
- *
- * @param type $v 要传入的组合阵列
- * @param type $keyname 对应的KEY名称。
- * @param type $valname 要写入的值KEY名称
- * @param type $s 重组译的阵例。预设空值。
- */
- function test($v,$keyname,$valname,$s=Array())
- {
- foreach($v AS $_k => $d)
- {
- $s[$d[$keyname]][$valname]= $d[$valname];
- }
- return $s;
- }
- $key ='server_id';
- foreach($arr1 as $k=>$v){
- $arr[$v['server_id']]= $v;
- }
- $data = test($arr2,$key,'arr2',$arr);
- $data = test($arr3,$key,'arr3',$data);