感谢 http://bbs.csdn.net/topics/391048578?page=1
create table A
(
[Id] [uniqueidentifier] NOT NULL,
[EventNo] [nvarchar](50) NULL,
[EventName] [nvarchar](200) NULL
) create table B
(
[Id] [uniqueidentifier] NOT NULL,
[AId] [uniqueidentifier] NULL,
[status] int,
[EventDetail] nvarchar(500) null
) Declare @Id [uniqueidentifier]
select @Id = NEWID()
insert into A select @Id,'','test1'
insert into B select NEWID(),@Id,0,'detail10'
insert into B select NEWID(),@Id,0,'detail11'
insert into B select NEWID(),@Id,3,'detail12' select @Id = NEWID()
insert into A select @Id,'','test2'
insert into B select NEWID(),@Id,0,'detail20'
insert into B select NEWID(),@Id,3,'detail21' select @Id = NEWID()
insert into A select @Id,'','test3' select @Id = NEWID()
insert into A select @Id,'','test4'
insert into B select NEWID(),@Id,0,'detail40'
insert into B select NEWID(),@Id,1,'detail41'
insert into B select NEWID(),@Id,3,'detail42' --
select A.EventNo,A.EventName,B.EventDetail From A left join B on a.Id = b.AId
EventNo EventName EventDetail
1 test1 detail10
1 test1 detail11
1 test1 detail12
2 test2 detail20
2 test2 detail21
3 test3 NULL
4 test4 detail40
4 test4 detail41
4 test4 detail42 --想要实际的效果为
EventNo EventName EventDetail
1 test1 detail10 2 test2 detail20
3 test3 NULL
4 test4 detail40
解决办法:
--方法1
SELECT A.EventNo,A.EventName,T2.EventDetail
FROM A
OUTER APPLY(SELECT TOP 1 EventDetail FROM B WHERE A.ID=B.AID ORDER BY status)T2 --方法2
SELECT EventNo,EventName,EventDetail
FROM(
SELECT A.EventNo,A.EventName,B.EventDetail
,ROW_NUMBER()OVER(PARTITION BY A.ID ORDER BY B.status)RN
FROM A
LEFT JOIN B ON A.ID=B.AID
--WHERE 其他条件 加在这最好
)T
WHERE RN=1
ORDER BY EventNo
方法一已经验证,可以使用。
对应自己数据库:
现在只有一个用户视图,需要select 单位并排序,因为一个单位有多个用户
select oaa.unitid,oaa.unitname,t2.DepartmentSortIndex from (
select * from ( select distinct(o.UnitId),o.UnitName from [McsDW].[dbo].[UserViewAll_DW] o) oa) oaa
outer apply (SELECT TOP 1 DepartmentSortIndex FROM [McsDW].[dbo].[UserViewAll_DW] B WHERE oaa.UnitId=B.UnitId ORDER BY DepartmentSortIndex) t2
order by DepartmentSortIndex