I have a DateTime object in Rails which outputs like this when called:
我在Rails中有一个DateTime对象,在调用时输出如下:
ruby-1.8.7-p302 > Time.now
=> Wed Nov 10 16:46:51 -0800 2010
How do I convert the DateObject to return an XML datetime type string like this:
如何转换DateObject以返回XML日期时间类型字符串,如下所示:
ruby-1.8.7-p302 > Time.now.convert_to_xml
=> 2010-11-10T16:46:51-08:00
4 个解决方案
#1
25
Time to XML format:
时间到XML格式:
Time.now.xmlschema # implemented by Rails, not stock ruby
Time.now.strftime '%Y-%m-%dT%H:%M:%S%z'
http://corelib.rubyonrails.org/classes/Time.html#M000281
http://corelib.rubyonrails.org/classes/Time.html#M000281
To parse (Ruby 1.9 and beyond):
要解析(Ruby 1.9及更高版本):
t = Time.now.xmlschema(str)
http://ruby-doc.org/core-1.9/classes/Time.html#M000329
http://ruby-doc.org/core-1.9/classes/Time.html#M000329
#2
5
Try Time.now.iso8601
试试Time.now.iso8601
#3
1
Here's a pure-Ruby way:
这是一种纯Ruby方式:
Time.now.strftime("%Y-%m-%dT%H:%M:%S%z")
You can get more details about the various strftime options with:
您可以通过以下方式获得有关各种strftime选项的更多详细信息:
ri Time.strftime
#1
25
Time to XML format:
时间到XML格式:
Time.now.xmlschema # implemented by Rails, not stock ruby
Time.now.strftime '%Y-%m-%dT%H:%M:%S%z'
http://corelib.rubyonrails.org/classes/Time.html#M000281
http://corelib.rubyonrails.org/classes/Time.html#M000281
To parse (Ruby 1.9 and beyond):
要解析(Ruby 1.9及更高版本):
t = Time.now.xmlschema(str)
http://ruby-doc.org/core-1.9/classes/Time.html#M000329
http://ruby-doc.org/core-1.9/classes/Time.html#M000329
#2
5
Try Time.now.iso8601
试试Time.now.iso8601
#3
1
Here's a pure-Ruby way:
这是一种纯Ruby方式:
Time.now.strftime("%Y-%m-%dT%H:%M:%S%z")
You can get more details about the various strftime options with:
您可以通过以下方式获得有关各种strftime选项的更多详细信息:
ri Time.strftime