Lets suppose that I have some pages
假设我有一些页面
some.web/articles/details/5
- some.web /文章/细节/ 5
some.web/users/info/bob
- some.web /用户/信息/鲍勃
some.web/foo/bar/7
- some.web / foo / bar / 7
that can call a common utility controller like
这可以调用一个通用的实用程序控制器。
locale/change/es
or authorization/login
地区/改变/ es或授权/登录
How do I get these methods (change
, login
) to redirect to the previous actions (details
, info
, bar
) while passing the previous parameters to them (5
, bob
, 7
)?
如何让这些方法(更改、登录)重定向到以前的操作(详细信息、信息、栏),同时将以前的参数传递给它们(5、bob、7)?
In short: How do I redirect to the page that I just visited after performing an action in another controller?
简而言之:如何在另一个控制器中执行操作后重定向到刚才访问的页面?
9 个解决方案
#1
127
try:
试一试:
public ActionResult MyNextAction()
{
return Redirect(Request.UrlReferrer.ToString());
}
alternatively, touching on what darin said, try this:
或者,谈谈darin所说的,试试这个:
public ActionResult MyFirstAction()
{
return RedirectToAction("MyNextAction",
new { r = Request.Url.ToString() });
}
then:
然后:
public ActionResult MyNextAction()
{
return Redirect(Request.QueryString["r"]);
}
#2
35
If you want to redirect from a button in the View you could use:
如果要从视图中的按钮重定向,可以使用:
@Html.ActionLink("Back to previous page", null, null, null, new { href = Request.UrlReferrer})
#3
25
If you are not concerned with unit testing then you can simply write:
如果您不关心单元测试,那么您可以简单地写:
return Redirect(ControllerContext.HttpContext.Request.UrlReferrer.ToString());
#4
8
A suggestion for how to do this such that:
关于如何这样做的建议:
- the return url survives a form's POST request (and any failed validations)
- 返回url经受住表单的POST请求(以及任何失败的验证)
- the return url is determined from the initial referral url
- 返回url由初始的引用url决定
- without using TempData[] or other server-side state
- 不使用TempData[]或其他服务器端状态
- handles direct navigation to the action (by providing a default redirect)
- 处理指向操作的直接导航(通过提供默认重定向)
.
。
public ActionResult Create(string returnUrl)
{
// If no return url supplied, use referrer url.
// Protect against endless loop by checking for empty referrer.
if (String.IsNullOrEmpty(returnUrl)
&& Request.UrlReferrer != null
&& Request.UrlReferrer.ToString().Length > 0)
{
return RedirectToAction("Create",
new { returnUrl = Request.UrlReferrer.ToString() });
}
// Do stuff...
MyEntity entity = GetNewEntity();
return View(entity);
}
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult Create(MyEntity entity, string returnUrl)
{
try
{
// TODO: add create logic here
// If redirect supplied, then do it, otherwise use a default
if (!String.IsNullOrEmpty(returnUrl))
return Redirect(returnUrl);
else
return RedirectToAction("Index");
}
catch
{
return View(); // Reshow this view, with errors
}
}
You could use the redirect within the view like this:
您可以使用视图中的重定向如下:
<% if (!String.IsNullOrEmpty(Request.QueryString["returnUrl"])) %>
<% { %>
<a href="<%= Request.QueryString["returnUrl"] %>">Return</a>
<% } %>
#5
6
Pass a returnUrl parameter (url encoded) to the change and login actions and inside redirect to this given returnUrl. Your login action might look something like this:
将returnUrl参数(url编码)传递到更改和登录操作,并在内部重定向到给定的returnUrl。您的登录操作可能是这样的:
public ActionResult Login(string returnUrl)
{
// Do something...
return Redirect(returnUrl);
}
#6
6
In Mvc using plain html in View Page with java script onclick
在Mvc中,在视图页面中使用纯html和java脚本onclick
<input type="button" value="GO BACK" class="btn btn-primary"
onclick="location.href='@Request.UrlReferrer'" />
This works great. hope helps someone.
这是伟大的。希望可以帮助别人。
@JuanPieterse has already answered using @Html.ActionLink
so if possible someone can comment or answer using @Url.Action
@JuanPieterse已经使用@Html回复。ActionLink,如果可能的话,某人可以使用@Url.Action评论或回答
#7
2
I'm using .Net Core 2 MVC , and this one worked for me, in the controller use HttpContext.Request.Headers["Referer"];
我使用。net Core 2 MVC,这个在控制器中使用httpcontext。request。header ["Referer"];
#8
1
You could return to the previous page by using ViewBag.ReturnUrl
property.
您可以使用ViewBag返回到前一页。ReturnUrl财产。
#9
1
To dynamically construct the returnUrl in any View, try this:
要动态构建returnUrl,请尝试以下方法:
@{
var formCollection =
new FormCollection
{
new FormCollection(Request.Form),
new FormCollection(Request.QueryString)
};
var parameters = new RouteValueDictionary();
formCollection.AllKeys
.Select(k => new KeyValuePair<string, string>(k, formCollection[k])).ToList()
.ForEach(p => parameters.Add(p.Key, p.Value));
}
<!-- Option #1 -->
@Html.ActionLink("Option #1", "Action", "Controller", parameters, null)
<!-- Option #2 -->
<a href="/Controller/Action/@object.ID?returnUrl=@Url.Action(ViewContext.RouteData.Values["action"].ToString(), ViewContext.RouteData.Values["controller"].ToString(), parameters)">Option #2</a>
<!-- Option #3 -->
<a href="@Url.Action("Action", "Controller", new { object.ID, returnUrl = Url.Action(ViewContext.RouteData.Values["action"].ToString(), ViewContext.RouteData.Values["controller"].ToString(), parameters) }, null)">Option #3</a>
This also works in Layout Pages, Partial Views and Html Helpers
这也适用于布局页面、部分视图和Html helper
Related: MVC3 Dynamic Return URL (Same but from within any Controller/Action)
相关:MVC3动态返回URL(相同但来自任何控制器/操作)
#1
127
try:
试一试:
public ActionResult MyNextAction()
{
return Redirect(Request.UrlReferrer.ToString());
}
alternatively, touching on what darin said, try this:
或者,谈谈darin所说的,试试这个:
public ActionResult MyFirstAction()
{
return RedirectToAction("MyNextAction",
new { r = Request.Url.ToString() });
}
then:
然后:
public ActionResult MyNextAction()
{
return Redirect(Request.QueryString["r"]);
}
#2
35
If you want to redirect from a button in the View you could use:
如果要从视图中的按钮重定向,可以使用:
@Html.ActionLink("Back to previous page", null, null, null, new { href = Request.UrlReferrer})
#3
25
If you are not concerned with unit testing then you can simply write:
如果您不关心单元测试,那么您可以简单地写:
return Redirect(ControllerContext.HttpContext.Request.UrlReferrer.ToString());
#4
8
A suggestion for how to do this such that:
关于如何这样做的建议:
- the return url survives a form's POST request (and any failed validations)
- 返回url经受住表单的POST请求(以及任何失败的验证)
- the return url is determined from the initial referral url
- 返回url由初始的引用url决定
- without using TempData[] or other server-side state
- 不使用TempData[]或其他服务器端状态
- handles direct navigation to the action (by providing a default redirect)
- 处理指向操作的直接导航(通过提供默认重定向)
.
。
public ActionResult Create(string returnUrl)
{
// If no return url supplied, use referrer url.
// Protect against endless loop by checking for empty referrer.
if (String.IsNullOrEmpty(returnUrl)
&& Request.UrlReferrer != null
&& Request.UrlReferrer.ToString().Length > 0)
{
return RedirectToAction("Create",
new { returnUrl = Request.UrlReferrer.ToString() });
}
// Do stuff...
MyEntity entity = GetNewEntity();
return View(entity);
}
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult Create(MyEntity entity, string returnUrl)
{
try
{
// TODO: add create logic here
// If redirect supplied, then do it, otherwise use a default
if (!String.IsNullOrEmpty(returnUrl))
return Redirect(returnUrl);
else
return RedirectToAction("Index");
}
catch
{
return View(); // Reshow this view, with errors
}
}
You could use the redirect within the view like this:
您可以使用视图中的重定向如下:
<% if (!String.IsNullOrEmpty(Request.QueryString["returnUrl"])) %>
<% { %>
<a href="<%= Request.QueryString["returnUrl"] %>">Return</a>
<% } %>
#5
6
Pass a returnUrl parameter (url encoded) to the change and login actions and inside redirect to this given returnUrl. Your login action might look something like this:
将returnUrl参数(url编码)传递到更改和登录操作,并在内部重定向到给定的returnUrl。您的登录操作可能是这样的:
public ActionResult Login(string returnUrl)
{
// Do something...
return Redirect(returnUrl);
}
#6
6
In Mvc using plain html in View Page with java script onclick
在Mvc中,在视图页面中使用纯html和java脚本onclick
<input type="button" value="GO BACK" class="btn btn-primary"
onclick="location.href='@Request.UrlReferrer'" />
This works great. hope helps someone.
这是伟大的。希望可以帮助别人。
@JuanPieterse has already answered using @Html.ActionLink
so if possible someone can comment or answer using @Url.Action
@JuanPieterse已经使用@Html回复。ActionLink,如果可能的话,某人可以使用@Url.Action评论或回答
#7
2
I'm using .Net Core 2 MVC , and this one worked for me, in the controller use HttpContext.Request.Headers["Referer"];
我使用。net Core 2 MVC,这个在控制器中使用httpcontext。request。header ["Referer"];
#8
1
You could return to the previous page by using ViewBag.ReturnUrl
property.
您可以使用ViewBag返回到前一页。ReturnUrl财产。
#9
1
To dynamically construct the returnUrl in any View, try this:
要动态构建returnUrl,请尝试以下方法:
@{
var formCollection =
new FormCollection
{
new FormCollection(Request.Form),
new FormCollection(Request.QueryString)
};
var parameters = new RouteValueDictionary();
formCollection.AllKeys
.Select(k => new KeyValuePair<string, string>(k, formCollection[k])).ToList()
.ForEach(p => parameters.Add(p.Key, p.Value));
}
<!-- Option #1 -->
@Html.ActionLink("Option #1", "Action", "Controller", parameters, null)
<!-- Option #2 -->
<a href="/Controller/Action/@object.ID?returnUrl=@Url.Action(ViewContext.RouteData.Values["action"].ToString(), ViewContext.RouteData.Values["controller"].ToString(), parameters)">Option #2</a>
<!-- Option #3 -->
<a href="@Url.Action("Action", "Controller", new { object.ID, returnUrl = Url.Action(ViewContext.RouteData.Values["action"].ToString(), ViewContext.RouteData.Values["controller"].ToString(), parameters) }, null)">Option #3</a>
This also works in Layout Pages, Partial Views and Html Helpers
这也适用于布局页面、部分视图和Html helper
Related: MVC3 Dynamic Return URL (Same but from within any Controller/Action)
相关:MVC3动态返回URL(相同但来自任何控制器/操作)