To show all methods defined by a particular class, but without methods that are defined in ancestors classes, I'm writing like this.
为了显示由特定类定义的所有方法，但是没有在祖先类中定义的方法，我这样编写。
foo.methods - foo.class.superclass.methods
Is there better way to do it?
有更好的办法吗?
1 个解决方案
#1
5
You can get instance methods with the following:
你可以获得实例方法如下:
foo.class.instance_methods(false)
as documented in http://ruby-doc.org/core-1.9.3/Module.html#method-i-instance_methods.
在http://ruby-doc.org/core-1.9.3/Module.html method-i-instance_methods记录。
The documentation for the parameter uses the term "superclasses" in describing what is included if the parameter is truthy, but based on my testing I believe all ancestor-provided methods are excluded/included based on this value, not just those from superclasses.
参数的文档使用术语“超类”来描述如果参数是真实的，将包含什么，但是根据我的测试，我认为所有祖先提供的方法都基于这个值被排除/包含，而不仅仅是超类的方法。
#1
5
You can get instance methods with the following:
你可以获得实例方法如下:
foo.class.instance_methods(false)
as documented in http://ruby-doc.org/core-1.9.3/Module.html#method-i-instance_methods.
在http://ruby-doc.org/core-1.9.3/Module.html method-i-instance_methods记录。
The documentation for the parameter uses the term "superclasses" in describing what is included if the parameter is truthy, but based on my testing I believe all ancestor-provided methods are excluded/included based on this value, not just those from superclasses.
参数的文档使用术语“超类”来描述如果参数是真实的，将包含什么，但是根据我的测试，我认为所有祖先提供的方法都基于这个值被排除/包含，而不仅仅是超类的方法。