无法解码来自NSXMLParser的UTF8字符

I use an XML parser to retrieve an xml from server.

我使用XML解析器从服务器检索XML。

And I have the following two things:

我有以下两点:

NSMutableArray *catalogueList;
Catalogue *currentCatalogue;

Catalogue looks like this:

目录如下:

#import "Catalogue.h"

@implementation Catalogue

@synthesize id_model;
@synthesize name;
@synthesize url;

@end

And this piece of code also:

这段代码也是:

- (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName{    
 if ([elementName isEqualToString:@"catalogue"]) 
{       
    // Add currentCatalogue to array
    [catalogueList addObject: currentCatalogue.url];
}

This works great, but there is a little problem. When I do this:

这很有效，但是有一个小问题。当我这样做:

 NSLog(@"Valoare url %@", currentCatalogue.url);

it displays the correct URL.

它显示正确的URL。

But when I do this:

但是当我这么做的时候:

 NSLog(@"Valoare url %@", catalogueList);

the output is "link".

输出是“链接”。

which is not correct at all: instead of Coupé I get Coup\U00e9. Please tell me how to obtain in catalogueList the correct link with the é character.

这一点也不正确:我得到的不是政变，而是政变。请告诉我如何在目录中找到正确的电子字符链接。

3 个解决方案

#1

You are printing an array instead of the object. Try this:

您正在打印一个数组而不是对象。试试这个:

NSLog(@"catalogueList url %@", [catalogueList objectAtIndex:0]);

Check out this SOF question NSLog incorrect encoding . Similar problems with UTF8 characters

检查这个NSLog错误编码的问题。UTF8字符也有类似的问题

#2

Make sure that your url property is a string in the array.

确保您的url属性是数组中的一个字符串。

@interface Catalogue : NSObject{

NSString *myURL;

}

NSString doesn't alter special characters, and should output the exact same thing that went in. The following Assumes you already added the string to the array.

NSString不改变特殊字符，应该输出与输入相同的内容。下面假定您已经将字符串添加到数组中。

NSLog(@"My URL: %@", [currentCatalogue objectAtIndex:0]);

Ouput: My URL: http://host_server/uploads/modeles_pdf/41_TTRS_Coupé_TTRS_Roadster_Tarifs_20110428.pdf

Also, Try doing this to see if you get the same error...

同样，试着这样做，看看你是否得到了同样的错误……

NSString *temp = currentCatalogue.url;
//Check the string
NSLog(@"NSString temp: %@", temp);

//Add it to the array
[catalogueList addObject:temp];

//Assuming object is at index 0, check the object in the array
NSLog(@"My URL: %@", [catalogueList objectAtIndex:0]);

#3

Get the UTF8 string value and use it

获取UTF8字符串值并使用它。

[currentCatalogue.url UTF8String];

#1