I have this PHP code:
我有这个PHP代码:
$end=date('Y-m-d');
I use it to get the current date, and I need the date 5 years in the future, something like:
我用它来获取当前日期,我需要未来5年的日期,比如:
$end=date('(Y + 5)-m-d');
How can I do this?
我该怎么做呢?
9 个解决方案
#1
103
Try with:
试一试:
$end = date('Y-m-d', strtotime('+5 years'));
#2
13
Modifying dates based on this post
strtotime() is really powerful and allows you to modify/transform dates easily with it’s relative expressions too:
Procedural
基于这个post strtotime()的修改日期非常强大,并且允许您轻松地修改/转换日期,它的相对表达式也是:过程性的。
$dateString = '2011-05-01 09:22:34';
$t = strtotime($dateString);
$t2 = strtotime('-3 days', $t);
echo date('r', $t2) . PHP_EOL; // returns: Thu, 28 Apr 2011 09:22:34 +0100
DateTime
DateTime
$dateString = '2011-05-01 09:22:34';
$dt = new DateTime($dateString);
$dt->modify('-3 days');
echo $dt->format('r') . PHP_EOL; // returns: Thu, 28 Apr 2011 09:22:34 +0100
The stuff you can throw at strtotime() is quite surprising and very human readable. Have a look at this example looking for Tuesday next week.
Procedural
你可以扔在strtotime()的东西是非常令人惊讶的,而且是人类可读的。请看下下周二的这个例子。程序上的
$t = strtotime("Tuesday next week");
echo date('r', $t) . PHP_EOL; // returns: Tue, 10 May 2011 00:00:00 +0100
DateTime
DateTime
$dt = new DateTime("Tuesday next week");
echo $dt->format('r') . PHP_EOL; // returns: Tue, 10 May 2011 00:00:00 +0100
Note that these examples above are being returned relative to the time now. The full list of time formats that strtotime() and the DateTime constructor takes are listed on the PHP Supported Date and Time Formats page.
请注意,上面的这些例子是相对于现在的时间返回的。strtotime()和DateTime构造函数所使用的时间格式的完整列表在PHP支持的日期和时间格式页面中列出。
Another example, suitable for your case could be: based on this post
另一个适合你的例子是:基于这篇文章。
<?php
//How to get the day 3 days from now:
$today = date("j");
$thisMonth = date("n");
$thisYear = date("Y");
echo date("F j Y", mktime(0,0,0, $thisMonth, $today+3, $thisYear));
//1 week from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth, $today+7, $thisYear));
//4 months from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth+4, $today, $thisYear));
//3 years, 2 months and 35 days from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth+2, $today+35, $thisYear+3));
?>
#3
6
Use this code to add years or months or days or hours or minutes or seconds to a given date
使用这段代码来添加数年、月、日、数或几分钟或几秒到某一特定日期。
echo date("Y-m-d H:i:s", strtotime("+1 years", strtotime('2014-05-22 10:35:10'))); //2015-05-22 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 months", strtotime('2014-05-22 10:35:10')));//2014-06-22 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 days", strtotime('2014-05-22 10:35:10')));//2014-05-23 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 hours", strtotime('2014-05-22 10:35:10')));//2014-05-22 11:35:10
echo date("Y-m-d H:i:s", strtotime("+1 minutes", strtotime('2014-05-22 10:35:10')));//2014-05-22 10:36:10
echo date("Y-m-d H:i:s", strtotime("+1 seconds", strtotime('2014-05-22 10:35:10')));//2014-05-22 10:35:11
You can also subtract replacing + to -
你也可以将替换替换为-。
#4
1
To add one year to todays date use the following:
增加一年的日期使用如下:
$oneYearOn = date('Y-m-d',strtotime(date("Y-m-d", mktime()) . " + 365 day"));
#5
1
$date = strtotime($row['timestamp']);
$newdate = date('d-m-Y',strtotime("+1 year",$date));
#7
0
try this ,
试试这个,
$presentyear = '2013-08-16 12:00:00';
$nextyear = date("M d,Y",mktime(0, 0, 0, date("m",strtotime($presentyear )), date("d",strtotime($presentyear )), date("Y",strtotime($presentyear ))+5));
echo $nextyear;
#8
0
Its very very easy with Carbon. $date = "2016-02-16"; // Or Your date $newDate = Carbon::createFromFormat('Y-m-d', $date)->addYear(1);
碳很容易。美元日期=“2016-02-16”;//或你的日期$newDate = Carbon::createFromFormat('Y-m-d', $date)->addYear(1);
#9
-1
try this:
试试这个:
$yearnow= date("Y");
$yearnext=$yearnow+1;
echo date("Y")."-".$yearnext;
#1
103
Try with:
试一试:
$end = date('Y-m-d', strtotime('+5 years'));
#2
13
Modifying dates based on this post
strtotime() is really powerful and allows you to modify/transform dates easily with it’s relative expressions too:
Procedural
基于这个post strtotime()的修改日期非常强大,并且允许您轻松地修改/转换日期,它的相对表达式也是:过程性的。
$dateString = '2011-05-01 09:22:34';
$t = strtotime($dateString);
$t2 = strtotime('-3 days', $t);
echo date('r', $t2) . PHP_EOL; // returns: Thu, 28 Apr 2011 09:22:34 +0100
DateTime
DateTime
$dateString = '2011-05-01 09:22:34';
$dt = new DateTime($dateString);
$dt->modify('-3 days');
echo $dt->format('r') . PHP_EOL; // returns: Thu, 28 Apr 2011 09:22:34 +0100
The stuff you can throw at strtotime() is quite surprising and very human readable. Have a look at this example looking for Tuesday next week.
Procedural
你可以扔在strtotime()的东西是非常令人惊讶的,而且是人类可读的。请看下下周二的这个例子。程序上的
$t = strtotime("Tuesday next week");
echo date('r', $t) . PHP_EOL; // returns: Tue, 10 May 2011 00:00:00 +0100
DateTime
DateTime
$dt = new DateTime("Tuesday next week");
echo $dt->format('r') . PHP_EOL; // returns: Tue, 10 May 2011 00:00:00 +0100
Note that these examples above are being returned relative to the time now. The full list of time formats that strtotime() and the DateTime constructor takes are listed on the PHP Supported Date and Time Formats page.
请注意,上面的这些例子是相对于现在的时间返回的。strtotime()和DateTime构造函数所使用的时间格式的完整列表在PHP支持的日期和时间格式页面中列出。
Another example, suitable for your case could be: based on this post
另一个适合你的例子是:基于这篇文章。
<?php
//How to get the day 3 days from now:
$today = date("j");
$thisMonth = date("n");
$thisYear = date("Y");
echo date("F j Y", mktime(0,0,0, $thisMonth, $today+3, $thisYear));
//1 week from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth, $today+7, $thisYear));
//4 months from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth+4, $today, $thisYear));
//3 years, 2 months and 35 days from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth+2, $today+35, $thisYear+3));
?>
#3
6
Use this code to add years or months or days or hours or minutes or seconds to a given date
使用这段代码来添加数年、月、日、数或几分钟或几秒到某一特定日期。
echo date("Y-m-d H:i:s", strtotime("+1 years", strtotime('2014-05-22 10:35:10'))); //2015-05-22 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 months", strtotime('2014-05-22 10:35:10')));//2014-06-22 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 days", strtotime('2014-05-22 10:35:10')));//2014-05-23 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 hours", strtotime('2014-05-22 10:35:10')));//2014-05-22 11:35:10
echo date("Y-m-d H:i:s", strtotime("+1 minutes", strtotime('2014-05-22 10:35:10')));//2014-05-22 10:36:10
echo date("Y-m-d H:i:s", strtotime("+1 seconds", strtotime('2014-05-22 10:35:10')));//2014-05-22 10:35:11
You can also subtract replacing + to -
你也可以将替换替换为-。
#4
1
To add one year to todays date use the following:
增加一年的日期使用如下:
$oneYearOn = date('Y-m-d',strtotime(date("Y-m-d", mktime()) . " + 365 day"));
#5
1
$date = strtotime($row['timestamp']);
$newdate = date('d-m-Y',strtotime("+1 year",$date));
#6
#7
0
try this ,
试试这个,
$presentyear = '2013-08-16 12:00:00';
$nextyear = date("M d,Y",mktime(0, 0, 0, date("m",strtotime($presentyear )), date("d",strtotime($presentyear )), date("Y",strtotime($presentyear ))+5));
echo $nextyear;
#8
0
Its very very easy with Carbon. $date = "2016-02-16"; // Or Your date $newDate = Carbon::createFromFormat('Y-m-d', $date)->addYear(1);
碳很容易。美元日期=“2016-02-16”;//或你的日期$newDate = Carbon::createFromFormat('Y-m-d', $date)->addYear(1);
#9
-1
try this:
试试这个:
$yearnow= date("Y");
$yearnext=$yearnow+1;
echo date("Y")."-".$yearnext;