python:代码复用与函数递归

 #recursion.py：打印斐波那契数列
 def fact(n):
     if n==1 or n==2:
         return 1
     else:
         return fact(n-1)+fact(n-2)
 while 1==1:
     test=eval(input("请输入数字："))
     for i in range(1,test+1):
         print("第{}次打印：".format(i),fact(i))