在href标记中获取字符串

I need a regex that will give me the string inside an href tag and inside the quotes also.

我需要一个regex，它将在href标记内和引号内为我提供字符串。

For example i need to extract theurltoget.com in the following:

例如，我需要将theurlt.com提取如下:

<a href="theurltoget.com">URL</a>

Additionally, I only want the base url part. I.e. from http://www.mydomain.com/page.html i only want http://www.mydomain.com/

另外，我只想要基本url部分。例如，从http://www.mydomain.com/page.html我只想要http://www.mydomain.com/

9 个解决方案

#1

Dont use regex for this. You can use xpath and built in php functions to get what you want:

不要为此使用regex。您可以使用xpath和内置的php函数来获得您想要的:

    $xml = simplexml_load_string($myHtml);
    $list = $xml->xpath("//@href");

    $preparedUrls = array();
    foreach($list as $item) {
        $item = parse_url($item);
        $preparedUrls[] = $item['scheme'] . '://' .  $item['host'] . '/';
    }
    print_r($preparedUrls);

#2

$html = '<a href="http://www.mydomain.com/page.html">URL</a>';

$url = preg_match('/<a href="(.+)">/', $html, $match);

$info = parse_url($match[1]);

echo $info['scheme'].'://'.$info['host']; // http://www.mydomain.com

#3

this expression will handle 3 options:

这个表达式将处理3个选项:

1. no quotes
2. 没有报价
3. double quotes
4. 双引号
5. single quotes
6. 单引号

'/href=["\']?([^"\'>]+)["\']?/'

' / href =[“\]?(\ ' >]+[^”)(“\”)? / '

#4

http://www.the-art-of-web.com/php/parse-links/

http://www.the-art-of-web.com/php/parse-links/

Let's start with the simplest case - a well formatted link with no extra attributes:

让我们从最简单的情况开始——一个格式良好、没有附加属性的链接:

/<a href=\"([^\"]*)\">(.*)<\/a>/iU

#5

Use the answer by @Alec if you're only looking for the base url part (the 2nd part of the question by @David)!

如果您只是在寻找基本url部分(问题的第二部分由@David提供)，请使用@Alec的答案!

$html = '<a href="http://www.mydomain.com/page.html" class="myclass" rel="myrel">URL</a>';
$url = preg_match('/<a href="(.+)">/', $html, $match);
$info = parse_url($match[1]);

This will give you:

这将给你:

$info
Array
(
    [scheme] => http
    [host] => www.mydomain.com
    [path] => /page.html" class="myclass" rel="myrel
)

So you can use $href = $info["scheme"] . "://" . $info["host"] Which gives you:

所以你可以使用$href = $info["scheme"]。”:/ /”。美元信息(“主机”)给你:

// http://www.mydomain.com  

---

When you are looking for the entire url between the href, You should be using another regex, for instance the regex provided by @user2520237.

在查找href之间的整个url时，应该使用另一个regex，例如@user2520237提供的regex。

$html = '<a href="http://www.mydomain.com/page.html" class="myclass" rel="myrel">URL</a>';
$url = preg_match('/href=["\']?([^"\'>]+)["\']?/', $html, $match);
$info = parse_url($match[1]);

this will give you:

这将给你:

$info
Array
(
    [scheme] => http
    [host] => www.mydomain.com
    [path] => /page.html
)

Now you can use $href = $info["scheme"] . "://" . $info["host"] . $info["path"]; Which gives you:

现在可以使用$href = $info["scheme"]。”:/ /”。美元的信息(“主机”)。$ info(“路径”);它给你:

// http://www.mydomain.com/page.html

#6

For all href values replacement:

所有href值替换:

function replaceHref($html, $replaceStr)
{
    $match = array();
    $url   = preg_match_all('/<a [^>]*href="(.+)"/', $html, $match);

    if(count($match))
    {
        for($j=0; $j<count($match); $j++)
        {
            $html = str_replace($match[1][$j], $replaceStr.urlencode($match[1][$j]), $html);
        }
    }
    return $html;
}
$replaceStr  = "http://affilate.domain.com?cam=1&url=";
$replaceHtml = replaceHref($html, $replaceStr);

echo $replaceHtml;

#7

This will handle the case where there are no quotes around the URL.

这将处理URL周围没有引号的情况。

/<a [^>]*href="?([^">]+)"?>/

But seriously, do not parse HTML with regex. Use DOM or a proper parsing library.

但认真地说，不要用regex解析HTML。使用DOM或适当的解析库。

#8

/href="(https?://[^/]*)/

I think you should be able to handle the rest.

我认为你应该能应付其余的事。

#9

Because Positive and Negative Lookbehind are cool

因为积极和消极的外表是很酷的。

/(?<=href=\").+(?=\")/

It will match only what you want, without quotation marks

它将只匹配你想要的，没有引号

Array ( [0] => theurltoget.com )

数组([0]=> theurlt.com)