For starters thank you for taking a look / any assistance you may offer.
对于初学者,感谢您查看/提供任何帮助。
I am trying to create a custom page template that creates a list in alphabetical order displaying all the results for a specific (Woocommerce) product attribute across my site.
我正在尝试创建一个自定义页面模板,按字母顺序创建一个列表,显示我网站上特定(Woocommerce)产品属性的所有结果。
So in my case the product attribute is "Artist"
所以在我的情况下,产品属性是“艺术家”
I found some code that does a similar thing for posts, which altered gives this:
我发现一些代码对帖子做了类似的事情,改变了这个:
<?php
/*
Template Name: Artists
*/
$posts_per_row = 4;
$posts_per_page = 400;
?>
<?php get_header(); ?>
<?php get_template_part( 'headers/page', 'header' ); ?>
<style type="text/css">
.letter-group { width: 100%; }
.letter-cell { width: 5%; height: 2em; text-align: center; padding-top: 8px; margin-bottom: 8px; float: left; }
.row-cells { width: 75%; float: right; margin-right: 180px; }
.title-cell { width: 25%; float: left; overflow: hidden; margin-bottom: 8px; }
.clear { clear: both; }
</style>
<div class="ps-container">
<div class="container clearfix">
<div id="main-background">
<div id="main-column">
<h1><?php the_title(); ?></h1>
<div class="margin-top"></div>
<div id="a-z">
<?php
$paged = (get_query_var('paged')) ? get_query_var('paged') : 1;
$args = array (
'posts_per_page' => $posts_per_page,
'post_type' => 'product',
'orderby' => 'title',
'order' => 'ASC',
'paged' => $paged
);
query_posts($args);
if ( have_posts() ) {
$in_this_row = 0;
while ( have_posts() ) {
the_post();
$first_letter = strtoupper(substr(apply_filters('the_title',$post->post_title),0,1));
if ($first_letter != $curr_letter) {
if (++$post_count > 1) {
end_prev_letter();
}
start_new_letter($first_letter);
$curr_letter = $first_letter;
}
if (++$in_this_row > $posts_per_row) {
end_prev_row();
start_new_row();
++$in_this_row; // Account for this first post
} ?>
<div class="title-cell"><a href="<?php the_permalink() ?>" rel="bookmark" title="Permanent Link to <?php the_title_attribute(); ?>"><?php the_title(); ?></a></div>
<?php }
end_prev_letter();
?>
<div class="navigation">
<div class="alignright"><?php next_posts_link('Next Page »') ?></div>
<div class="alignleft"><?php previous_posts_link('« Previous Page') ?></div>
</div>
<?php } else {
echo "<h2>Sorry, no artists were found!</h2>";
}
?>
</div><!-- End id='a-z' -->
</div><!-- End class='margin-top -->
</div><!-- End id='rightcolumn' -->
</div>
</div>
<?php get_footer(); ?>
<?php
function end_prev_letter() {
end_prev_row();
echo "</div><!-- End of letter-group -->\n";
echo "<div class='clear'></div>\n";
}
function start_new_letter($letter) {
echo "<div class='letter-group'>\n";
echo "\t<div class='letter-cell'>$letter</div>\n";
start_new_row($letter);
}
function end_prev_row() {
echo "\t</div><!-- End row-cells -->\n";
}
function start_new_row() {
global $in_this_row;
$in_this_row = 0;
echo "\t<div class='row-cells'>\n";
}
?>
Now to alter this, I tried using get attribute in place of the array retrieving my posts, as I normally do in other spots of my site using:
现在要改变这一点,我尝试使用get属性代替检索我的帖子的数组,就像我通常在我的网站的其他位置使用:
global $product;
$product->get_attribute( ‘pa_attribute’ )
But nothing is working.
但没有任何工作。
Can anyone shed some light on my issue? I get it showing posts just fine, but I can't transition this to properly list the Artists names instead of product (post) names.
有谁可以解释我的问题?我觉得它显示的帖子很好,但是我无法将其转换为正确列出艺术家名称而不是产品(帖子)名称。
Thank you.
1 个解决方案
#1
Merging the two examples in the Codex, and assuming your attribute is called "artist" then you'd get a list of terms like so:
合并Codex中的两个示例,并假设您的属性被称为“artist”,那么您将得到如下所示的术语列表:
$terms = get_terms( 'pa_artist' );
if ( ! empty( $terms ) && ! is_wp_error( $terms ) ){
echo '<ul>';
foreach ( $terms as $term ) {
echo '<li><a href="' . get_term_link( $term ) . '" title="' . sprintf( __( 'View all post filed under %s', 'my_localization_domain' ), $term->name ) . '">' . $term->name . '</a></li>';
}
echo '</ul>';
}
#1
Merging the two examples in the Codex, and assuming your attribute is called "artist" then you'd get a list of terms like so:
合并Codex中的两个示例,并假设您的属性被称为“artist”,那么您将得到如下所示的术语列表:
$terms = get_terms( 'pa_artist' );
if ( ! empty( $terms ) && ! is_wp_error( $terms ) ){
echo '<ul>';
foreach ( $terms as $term ) {
echo '<li><a href="' . get_term_link( $term ) . '" title="' . sprintf( __( 'View all post filed under %s', 'my_localization_domain' ), $term->name ) . '">' . $term->name . '</a></li>';
}
echo '</ul>';
}