I'm new to Laravel and I've been struggling too long with this now, tried to search SO and google for information but can't solve this.
我是Laravel的新手,我已经在这个问题上挣扎了太久了,我试着搜索SO和谷歌来寻找信息,但是无法解决这个问题。
I'm creating blog and need to make some kind of navigation/archive which displays year and months and how many blog posts there have been per year and invidual month. By clicking those years/months I would then display posts during that time period on different view.
我正在创建博客,需要做一些导航/存档,显示年份和月份,以及每年和每个月有多少博客文章。通过点击那些年/月,我将在那个时间段显示不同观点的帖子。
I want them to be displayed in the view like this:
我希望它们像这样显示在视图中:
2015 (10)
January(3)
February(3)
March(3)
April(1)
2014 (2)
May(1)
June(1)
And so on.
等等。
I got database query like this:
我得到这样的数据库查询:
$links = \DB::table('posts')
->select(\DB::raw('YEAR(created_at) year, MONTH(created_at) month, MONTHNAME(created_at) month_name, COUNT(*) id'))
->where('active',1)
->groupBy('year')
->groupBy('month')
->orderBy('year', 'desc')
->orderBy('month', 'desc')
->get();
Which gives me table like this:
我的桌子是这样的:
array:3 [
0 => {#275
+"year": "2015"
+"month": "10"
+"month_name": "October"
+"id": "3"
}
1 => {#274
+"year": "2015"
+"month": "9"
+"month_name": "September"
+"id": "1"
}
2 => {#273
+"year": "2014"
+"month": "8"
+"month_name": "August"
+"id": "1"
}
]
How can I print it on my view like I described? If I go through the array in views like this:
如何像我描述的那样在我的视图上打印它?如果我像这样在视图中遍历数组:
@foreach($links as $link)
<h3 class="text-uppercase"><a href="{{ url('blog/'.$link->year) }}">{{ $link->year }}</a></h3>
<p><small class="blog_date"><a href="{{ url('blog/'.$link->year.'/'.$link->month) }}">{{ $link->month_name }} ({{ $link->id }}) </a></small>
@endforeach
I tried to use foreach-loop in my Controller to create another array from DB-results where structure would be in correct form and I could just use foreach to print it on the view, but couldn't get it work.
我尝试在我的控制器中使用foreach-loop从DB-results中创建另一个数组,其中的结构应该是正确的形式,我可以使用foreach在视图上打印它,但是不能让它工作。
I know I'm near the solution, but I'm still learning. Please someone tell me which is the best way to do this.
我知道我已经接近解决方案了,但我还在学习。请告诉我哪一个是最好的方法。
2 个解决方案
#1
1
Try this in your blade:
在你的剑刃上试试这个:
<?php $first_loop = 0; ?>
@foreach($links as $link)
@if($first_loop == 0)
<?php
$first_loop = 1;
$current_year = $link->year;
?>
<h3 class="text-uppercase"><a href="{{ url('blog/'.$link->year) }}">{{ $link->year }}</a></h3>
<p><small class="blog_date"><a href="{{ url('blog/'.$link->year.'/'.$link->month) }}">{{ $link->month_name }} ({{ $link->id }}) </a></small></p>
@else
@if($current_year == $link->year)
<p><small class="blog_date"><a href="{{ url('blog/'.$link->year.'/'.$link->month) }}">{{ $link->month_name }} ({{ $link->id }}) </a></small></p>
<?php
$current_year = $link->year;
?>
@else
<h3 class="text-uppercase"><a href="{{ url('blog/'.$link->year) }}">{{ $link->year }}</a></h3>
<p><small class="blog_date"><a href="{{ url('blog/'.$link->year.'/'.$link->month) }}">{{ $link->month_name }} ({{ $link->id }}) </a></small></p>
<?php
$current_year = $link->year;
?>
@endif
@endif
@endforeach
#2
1
You can do some preparation on your data before outputting it. For example:
在输出数据之前,你可以对数据做一些准备。例如:
$links = // .. your query;
$years = array_pluck($links, 'year');
$results = [];
foreach($years as $year)
{
$posts_count = 0;
$posts = array_where($links, function($key, $value) use ($year, $posts_count){
if($value['year'] == $year)
{
$posts_count += $value['id'];
return true;
}
return false;
});
$results[$year] = ['posts' => $posts, 'posts_count' => $posts_count];
}
You can do the above in some repository/service class, or even in the controller if you want (although not recommended)
您可以在某些存储库/服务类中执行上述操作,甚至可以在控制器中执行(尽管不建议这样做)
And then in your view you can have something like:
在你看来
@foreach($results as $year => $result)
<a href="">{{ $year }} {{ data_get($result, 'posts_count') }}</a>
<ul>
@foreach(data_get($result, 'posts') as $monthly_post)
<li><a href="">{{ data_get($monthly_post, 'month_name') }} {{ data_get($monthly_post, 'id') }}</a></li>
@endforeach
</ul>
@endforeach
This code is untested, so use it as inspiration for your approach, not a copy-paste solution.
这段代码没有经过测试,所以请将它作为您的方法的灵感,而不是复制粘贴解决方案。
#1
1
Try this in your blade:
在你的剑刃上试试这个:
<?php $first_loop = 0; ?>
@foreach($links as $link)
@if($first_loop == 0)
<?php
$first_loop = 1;
$current_year = $link->year;
?>
<h3 class="text-uppercase"><a href="{{ url('blog/'.$link->year) }}">{{ $link->year }}</a></h3>
<p><small class="blog_date"><a href="{{ url('blog/'.$link->year.'/'.$link->month) }}">{{ $link->month_name }} ({{ $link->id }}) </a></small></p>
@else
@if($current_year == $link->year)
<p><small class="blog_date"><a href="{{ url('blog/'.$link->year.'/'.$link->month) }}">{{ $link->month_name }} ({{ $link->id }}) </a></small></p>
<?php
$current_year = $link->year;
?>
@else
<h3 class="text-uppercase"><a href="{{ url('blog/'.$link->year) }}">{{ $link->year }}</a></h3>
<p><small class="blog_date"><a href="{{ url('blog/'.$link->year.'/'.$link->month) }}">{{ $link->month_name }} ({{ $link->id }}) </a></small></p>
<?php
$current_year = $link->year;
?>
@endif
@endif
@endforeach
#2
1
You can do some preparation on your data before outputting it. For example:
在输出数据之前,你可以对数据做一些准备。例如:
$links = // .. your query;
$years = array_pluck($links, 'year');
$results = [];
foreach($years as $year)
{
$posts_count = 0;
$posts = array_where($links, function($key, $value) use ($year, $posts_count){
if($value['year'] == $year)
{
$posts_count += $value['id'];
return true;
}
return false;
});
$results[$year] = ['posts' => $posts, 'posts_count' => $posts_count];
}
You can do the above in some repository/service class, or even in the controller if you want (although not recommended)
您可以在某些存储库/服务类中执行上述操作,甚至可以在控制器中执行(尽管不建议这样做)
And then in your view you can have something like:
在你看来
@foreach($results as $year => $result)
<a href="">{{ $year }} {{ data_get($result, 'posts_count') }}</a>
<ul>
@foreach(data_get($result, 'posts') as $monthly_post)
<li><a href="">{{ data_get($monthly_post, 'month_name') }} {{ data_get($monthly_post, 'id') }}</a></li>
@endforeach
</ul>
@endforeach
This code is untested, so use it as inspiration for your approach, not a copy-paste solution.
这段代码没有经过测试,所以请将它作为您的方法的灵感,而不是复制粘贴解决方案。