i really don't understand how to handle with post data from ajax request. This is my javascript:
我真的不明白如何处理来自ajax请求的帖子数据。这是我的javascript:
$.ajax({
type: "POST",
url: Routing.generate('save'),
contentType: 'application/json; charset=UTF-8',
data: {
title: title,
description: description,
questions: questions,
}
});
The only way to get the data inside my controller action is this:
在控制器操作中获取数据的唯一方法是:
$content = $request->getContent()
$content is a url parameter string. Why don't i get the data normally with:
$ content是url参数字符串。为什么我没有正常获取数据:
$request->get('title')
What is the correct way to handle the post data with jquery ajax methd?
使用jquery ajax方法处理post数据的正确方法是什么?
Thank you very much.
非常感谢你。
EDIT
编辑
So, i found out the following issue:
所以,我发现了以下问题:
In my current project the request looks like this:
在我当前的项目中,请求如下所示:
$.ajax({
type: "POST",
url: Routing.generate('poll_save'),
data: {
title: title
}
})
The data is requested via Request Payload but i don't know why.
数据是通过Request Payload请求的,但我不知道为什么。
In a clean project the request looks like this:
在一个干净的项目中,请求如下所示:
$.ajax({
type: "POST",
url: '{{path('_demo')}}',
data: {
title: 'title',
description: 'description',
questions: 'questions',
pollid: 1
}
})
Anything in my project is going wrong. Do you have an idea why the data is requested via Request Payload?
我项目中的任何内容都出错了。您是否知道为什么通过请求有效负载请求数据?
4 个解决方案
#1
9
Do you use the request object in your controller?
你在控制器中使用请求对象吗?
<?php
namespace Acme\DemoBundle\Controller;
use Symfony\Component\HttpFoundation\Request;
//...other things to use
class MyController extends Controller
{
public function handleRequestAction() {
$request = $this->get('request');
//request your data
$title = $request->get('title');
//or in one line
$title = $this->get('request')->request->get('title');
}
}
?>
This is my normal way when I want to get data from an ajax call. Could you post what $content contains?
当我想从ajax调用中获取数据时,这是我的正常方式。你能发布$ content包含的内容吗?
I see no problem with posting the data like you did. Constructing a json object might be helpful but the way you're doing it seems fine to me. I did this too.
我发现像你一样发布数据没问题。构造一个json对象可能会有所帮助,但是你这样做的方式对我来说似乎很好。我也是这样做的。
EDIT
编辑
Normally you could also access all data in the request by doing this:
通常,您还可以通过执行以下操作来访问请求中的所有数据:
$all = $request->request->all();
Maybe you could then var_dump()
the variables to see if something is in them.
也许你可以然后var_dump()变量,看看是否有东西。
#2
1
You can construct your json object and pass the JSON object to your controller using JSON.stringify.
您可以使用JSON.stringify构造json对象并将JSON对象传递给控制器。
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/JSON/stringify
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/JSON/stringify
var obj = {
title: title,
description: description,
questions: questions
};
$.ajax({
type: "POST",
url: Routing.generate('save'),
contentType: 'application/json; charset=UTF-8',
data: JSON.stringify(obj)
});
#3
1
quiz - form name serialize -populate the variables
测验 - 表格名称序列化 - 填充变量
$.ajax({
url: $("#quiz").attr("action"),
data: $("#quiz").serialize(),
type: 'POST'
});
or
要么
$.ajax({
url: $("#commentForm").attr("action"),
data: {
comment: commentFormID.val()
},
type: 'POST'
});
Controller - More like what previous comments suggested.
控制器 - 更像以前的评论建议。
$request = $this->get('request');
$usercomment=$request->request->get('parameterName');
#4
0
Why Json? I meant is a requirement to content type json? if not, this is the way I handle ajax and using FOSRoutingbundle that I can see you are using.
为何选择Json?我的意思是内容类型json的要求?如果没有,这是我处理ajax和使用FOSRoutingbundle的方式,我可以看到你正在使用。
$(document).ready(function(){
$('#myForm').submit( function(e){
e.preventDefault();
var $form = $(this);
var $formPHP = $form.serializeArray();
var $url = Routing.generate( 'route_to_use');
$.post( $url, $formPHP, function(data){
.....
});
});
});
Then in the controller you can use as a normal request.
然后在控制器中,您可以将其用作普通请求。
#1
9
Do you use the request object in your controller?
你在控制器中使用请求对象吗?
<?php
namespace Acme\DemoBundle\Controller;
use Symfony\Component\HttpFoundation\Request;
//...other things to use
class MyController extends Controller
{
public function handleRequestAction() {
$request = $this->get('request');
//request your data
$title = $request->get('title');
//or in one line
$title = $this->get('request')->request->get('title');
}
}
?>
This is my normal way when I want to get data from an ajax call. Could you post what $content contains?
当我想从ajax调用中获取数据时,这是我的正常方式。你能发布$ content包含的内容吗?
I see no problem with posting the data like you did. Constructing a json object might be helpful but the way you're doing it seems fine to me. I did this too.
我发现像你一样发布数据没问题。构造一个json对象可能会有所帮助,但是你这样做的方式对我来说似乎很好。我也是这样做的。
EDIT
编辑
Normally you could also access all data in the request by doing this:
通常,您还可以通过执行以下操作来访问请求中的所有数据:
$all = $request->request->all();
Maybe you could then var_dump()
the variables to see if something is in them.
也许你可以然后var_dump()变量,看看是否有东西。
#2
1
You can construct your json object and pass the JSON object to your controller using JSON.stringify.
您可以使用JSON.stringify构造json对象并将JSON对象传递给控制器。
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/JSON/stringify
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/JSON/stringify
var obj = {
title: title,
description: description,
questions: questions
};
$.ajax({
type: "POST",
url: Routing.generate('save'),
contentType: 'application/json; charset=UTF-8',
data: JSON.stringify(obj)
});
#3
1
quiz - form name serialize -populate the variables
测验 - 表格名称序列化 - 填充变量
$.ajax({
url: $("#quiz").attr("action"),
data: $("#quiz").serialize(),
type: 'POST'
});
or
要么
$.ajax({
url: $("#commentForm").attr("action"),
data: {
comment: commentFormID.val()
},
type: 'POST'
});
Controller - More like what previous comments suggested.
控制器 - 更像以前的评论建议。
$request = $this->get('request');
$usercomment=$request->request->get('parameterName');
#4
0
Why Json? I meant is a requirement to content type json? if not, this is the way I handle ajax and using FOSRoutingbundle that I can see you are using.
为何选择Json?我的意思是内容类型json的要求?如果没有,这是我处理ajax和使用FOSRoutingbundle的方式,我可以看到你正在使用。
$(document).ready(function(){
$('#myForm').submit( function(e){
e.preventDefault();
var $form = $(this);
var $formPHP = $form.serializeArray();
var $url = Routing.generate( 'route_to_use');
$.post( $url, $formPHP, function(data){
.....
});
});
});
Then in the controller you can use as a normal request.
然后在控制器中,您可以将其用作普通请求。