So, how can I tell the system to open the file for me? I've tried
那么，我如何告诉系统为我打开文件？我试过了
Shell(ExcelFilePath)
But an exception was thrown although the file path is from OpenFileDialog.FileOk
但是，虽然文件路径来自OpenFileDialog.FileOk，但抛出异常
So, I am trying to play with Excel.Application, is it possible to open the file with that?
所以，我正在尝试使用Excel.Application，是否可以用它打开文件？
2 个解决方案
#1
7
This will open the file with Excel:
这将使用Excel打开文件：
Process.Start("EXCEL.EXE", """C:\Folder\file.xls""")
Being the second string the arguments for the process. See the MSDN Dcoumentation.
作为第二个字符串的过程参数。请参阅MSDN Dcoumentation。
#2
4
try this
尝试这个
System.Diagnostics.Process.Start("FilePath")
it will open the file in an application associated with it.
它将在与之关联的应用程序中打开该文件。
#1
7
This will open the file with Excel:
这将使用Excel打开文件：
Process.Start("EXCEL.EXE", """C:\Folder\file.xls""")
Being the second string the arguments for the process. See the MSDN Dcoumentation.
作为第二个字符串的过程参数。请参阅MSDN Dcoumentation。
#2
4
try this
尝试这个
System.Diagnostics.Process.Start("FilePath")
it will open the file in an application associated with it.
它将在与之关联的应用程序中打开该文件。