I have to allow only Debit/Credit card number format in asp.net textbox. Below is a sample screenshot-
我只允许在asp.net文本框中使用借记卡/信用卡号格式。下面是一个截图示例
Please let me know how to do this with asp.net textbox and I don't have to use validators.
请告诉我如何使用asp.net文本框,我不需要使用验证器。
Note: I only have to allow numbers and after every 4 numbers there should be a hyphen(-).
注意:我只允许数字,在每4个数字之后应该有一个连字符(-)。
3 个解决方案
#1
1
I would strongly recommend you not to reinvent the bicycle and use jQuery inputmask plugin which will let you do the following:
我强烈建议你不要重新发明这款自行车,使用jQuery inputmask插件,它可以让你完成以下工作:
$("input").inputmask({
mask: "9999 9999 9999 9999",
placeholder: ""
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery.inputmask/3.3.4/jquery.inputmask.bundle.js"></script>
<input type="text"/>
Note that in this code I assumed that card number consists of 4 groups of 4 digits each, and it is not always true - it depends on expected cards' payment systems, country etc.
You can easily achieve any result by adding or removing digits in mask.
注意,在这段代码中,我假设每个卡号由4组4位数字组成,而且它并不总是正确的——它取决于预期的卡的支付系统、国家等。
#2
0
Using vanilla javascript
使用香草javascript
document.getElementById('inp1').onkeypress = verify;
console.clear();
function isKeyValid(key) {
if(key > 47 && key < 58) return true
else if(key === 45) return true;
else return false;
}
function isValidCard(arr, isDash) {
const last = arr[arr.length - 1];
if(last.length === 4 && !isDash) return false;
else if(isDash && last.length !== 4) return false;
else if(isDash && arr.length === 4) return false;
else return true;
}
function verify(e) {
const key = e.keyCode || e.which;
const isDash = key === 45;
const val = e.target.value;
const input = val.split('-');
if (!isKeyValid(key) || !isValidCard(input, isDash)) {
return e.preventDefault();
}
// ...do something
}
#3
0
You can do the following:
你可以做以下事情:
<input type="text" onkeypress="return allowNumbersAndHyphen(event)">
function allowNumbersAndHyphen(evt) {
var charCode = (evt.which) ? evt.which : event.keyCode;
//allowing numbers, left key(37) right key(39) backspace(8) delete(46) and hyphen(45)
var length = $('input').val().length;
if (((charCode == 37 || charCode == 39 || charCode == 8 || charCode == 46 || charCode == 45) || !(charCode > 31 && (charCode < 48 || charCode > 57))) && length <19)
{
return true;
}
else{
return false;
}
}
//put hyphens atomatically
$(document).ready(function(){
$('input').on('keypress', function() {
var temp = $(this).val();
if (temp.length == 4 || temp.length == 9 || temp.length == 14) {
$('input').val(temp + '-');
}
});
$('input').on('blur', function() {
var regex = /^[0-9]{4}-[0-9]{4}-[0-9]{4}-[0-9]{4}$/;
var cardNumber = $(this).val();
if(regex.test(cardNumber)) {
//success
alert('successful');
}
else {
//show your error
alert('Error');
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<!-- begin snippet: js hide: false console: true babel: false -->
#1
1
I would strongly recommend you not to reinvent the bicycle and use jQuery inputmask plugin which will let you do the following:
我强烈建议你不要重新发明这款自行车,使用jQuery inputmask插件,它可以让你完成以下工作:
$("input").inputmask({
mask: "9999 9999 9999 9999",
placeholder: ""
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery.inputmask/3.3.4/jquery.inputmask.bundle.js"></script>
<input type="text"/>
Note that in this code I assumed that card number consists of 4 groups of 4 digits each, and it is not always true - it depends on expected cards' payment systems, country etc.
You can easily achieve any result by adding or removing digits in mask.
注意,在这段代码中,我假设每个卡号由4组4位数字组成,而且它并不总是正确的——它取决于预期的卡的支付系统、国家等。
#2
0
Using vanilla javascript
使用香草javascript
document.getElementById('inp1').onkeypress = verify;
console.clear();
function isKeyValid(key) {
if(key > 47 && key < 58) return true
else if(key === 45) return true;
else return false;
}
function isValidCard(arr, isDash) {
const last = arr[arr.length - 1];
if(last.length === 4 && !isDash) return false;
else if(isDash && last.length !== 4) return false;
else if(isDash && arr.length === 4) return false;
else return true;
}
function verify(e) {
const key = e.keyCode || e.which;
const isDash = key === 45;
const val = e.target.value;
const input = val.split('-');
if (!isKeyValid(key) || !isValidCard(input, isDash)) {
return e.preventDefault();
}
// ...do something
}
#3
0
You can do the following:
你可以做以下事情:
<input type="text" onkeypress="return allowNumbersAndHyphen(event)">
function allowNumbersAndHyphen(evt) {
var charCode = (evt.which) ? evt.which : event.keyCode;
//allowing numbers, left key(37) right key(39) backspace(8) delete(46) and hyphen(45)
var length = $('input').val().length;
if (((charCode == 37 || charCode == 39 || charCode == 8 || charCode == 46 || charCode == 45) || !(charCode > 31 && (charCode < 48 || charCode > 57))) && length <19)
{
return true;
}
else{
return false;
}
}
//put hyphens atomatically
$(document).ready(function(){
$('input').on('keypress', function() {
var temp = $(this).val();
if (temp.length == 4 || temp.length == 9 || temp.length == 14) {
$('input').val(temp + '-');
}
});
$('input').on('blur', function() {
var regex = /^[0-9]{4}-[0-9]{4}-[0-9]{4}-[0-9]{4}$/;
var cardNumber = $(this).val();
if(regex.test(cardNumber)) {
//success
alert('successful');
}
else {
//show your error
alert('Error');
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<!-- begin snippet: js hide: false console: true babel: false -->