星期几到星期数（星期一= 1，星期二= 2）

Does php have a function to automatically convert dates to their day value, where Monday=1, Tuesday=2, etc. Something like this

php是否具有自动将日期转换为日期值的功能，其中Monday = 1，Tuesday = 2等。这样的事情

$daynum = func('wednesday'); //echos 3

5 个解决方案

#1

$day_of_week = date('N', strtotime('Monday'));

#2

What about using idate()? idate()

那么使用idate（）呢？ IDATE（）

$integer = idate('w', $timestamp);

#3

$day_number = date('N', $date);

This will return a 1 for Monday to 7 for Sunday, for the date that is stored in $date. Omitting the second argument will cause date() to return the number for the current day.

对于存储在$ date中的日期，这将在星期一将1返回到星期日的7。省略第二个参数将导致date（）返回当前日期的数字。

#4

The date function can return this if you specify the format correctly:

如果正确指定格式，则date函数可以返回此值：

$daynum = date("w", strtotime("wednesday"));

will return 0 for Sunday through to 6 for Saturday.

周日将返回0，周六返回6。

An alternative format is:

另一种格式是：

$daynum = date("N", strtotime("wednesday"));

which will return 1 for Monday through to 7 for Sunday (this is the ISO-8601 represensation).

星期一将返回1，星期日返回7（这是ISO-8601代表）。

#5

$tm = localtime($timestamp, TRUE);
$dow = $tm['tm_wday'];

Where $dow is the day of (the) week. Be aware of the herectic approach of localtime, though (pun): Sunday is not the last day of the week, but the first (0).

其中$ dow是（星期）的一天。请注意本地时间的近似方法，但是（双关语）：星期日不是一周中的最后一天，而是第一天（0）。

#1

$day_of_week = date('N', strtotime('Monday'));

#2