如何连接到线路上的插件路由。php文件CAKEPHP

I have a plugin named Manager. I want to map route on /login to the index action of Dashboard Controller on plugin. Something like this:

我有一个叫“经理”的插件。我想要在插件上将路径映射到仪表板控制器的索引操作。是这样的:

Router::connect('/login', array('controller' => 'dashboard', 'action' => 'index', 'plugin => 'manager'));

How can I achieve this on Cakephp 2.2?

如何在Cakephp 2.2中实现这一点?

thanks

谢谢

2 个解决方案

#1

Once a plugin has been installed in /app/Plugin, you can access it at the URL /plugin_name/controller_name/action. In your Manager plugin example, you'd access DashboardController at /manager/dashboard.

一旦插件安装在/app/插件中，你就可以在URL /plugin_name/controller_name/action中访问它。在您的Manager plugin示例中，您将访问/ Manager /仪表板上的DashboardController。

Have you tries using Plugin Syntax, like:

你试过使用插件语法吗?

Router::connect('/login', 
    array('controller' => 'Manager.dashboard', 'action' => 'index')
);

Using the 'plugin' key in the $options array should also do the job:

在$options数组中使用“插件”键也可以完成任务:

Router::connect('/login', 
    array('plugin' => 'manager','controller' => 'dashboard', 'action' => 'index')
);

#2

If use plugin like 'users plugin' try in plugin's routes file (routes.php)

如果在插件的路由文件中使用“用户插件”这样的插件。

#1