Hi I need to get data from a database but I can't figure out how do do it as is...
嗨,我需要从数据库中获取数据,但我无法弄清楚它是如何做到的......
They have "boutiques" tables and "boutiques_categories" and a relation table between them name "boutiques_categories_categories"
他们有“精品店”桌子和“boutiques_categories”,他们之间的关系表名称为“boutiques_categories_categories”
here how they are setup :
这里是如何设置的:
boutiques
id name
1 X_boutiques2_name
2 Y_boutiques_name
Boutique2
id name
1 X_boutiques2_name
2 Y_boutiques2_name
boutiques_categories
id name
1 X_categorie_name
2 Y_categorie_name
boutiques_categories_categories
boutique_id categorie_id
X_boutique_id X_categorie_id
Y_boutique_id Y_categorie_id
I want to create a SQL to merge and print a CSV of the data like so :
我想创建一个SQL来合并和打印数据的CSV,如下所示:
export
boutiques_id boutique_name boutiques_categories_categorie_name
boutiques2_id boutique2_name boutiques_categories_categorie_name
I trying UNION those 2 table
我试着UNION那两张桌子
SELECT A.*
FROM boutiques A
UNION select B.* FROM boutiques2 B
And it's working but now I need to Join the categorie name to it and I can't figure out how to do it. Tried :
它正在工作,但现在我需要加入类别名称,我无法弄清楚如何做到这一点。试过:
SELECT A.*
FROM boutiques A
UNION select B.*
FROM boutiques2 B
left join
boutiques_categories BC ON BC.id =
(
SELECT BCC.categorie_id
FORM
boutiques_categories_categories BCC
WHERE BCC.boutique_id = BC.id
)
But I get MYSQL error that I can't resolve.
但我得到MYSQL错误,我无法解决。
#1242 - Subquery returns more than 1 row
Thank for your time.
谢谢你的时间。
1 个解决方案
#1
2
You can union (or union all
, depending on what data you want) boutiques
and Boutique2
into a derived table, and then join that to boutiques_categories through boutiques_categories_categories.
您可以将精品店和精品店2联合(或联合所有,具体取决于您想要的数据)到派生表中,然后通过boutiques_categories_categories将其加入boutiques_categories。
The table data that you included in your question doesn't seem completely accurate though. Specifically: boutiques_categories_categories containing boutique_id and categorie_id values that don't match the id columns of the associated tables. I'm just going to assume that boutiques_categories_categories have int ID values. If this is not the case, please clarify in the comments, and I can adjust the query appropriately.
您在问题中包含的表格数据似乎并不完全准确。具体来说:boutiques_categories_categories包含与相关表的id列不匹配的boutique_id和categorie_id值。我只是假设boutiques_categories_categories有int ID值。如果不是这种情况,请在评论中说明,我可以适当调整查询。
Give this query a try, and see if it returns the data that you expect:
尝试使用此查询,看看它是否返回您期望的数据:
select
b.id, b.name, c.name
from
-- Get the boutiques rows from the unioned tables
(
select id, name from boutiques
union
select id, name from Boutique2
) as b
-- Join in boutiques_cateogires_categories
join boutiques_categories_categories cc
on (b.id=cc.boutique_id)
-- Join in boutiques_categories
join boutiques_categories c
on (cc.categorie_id=c.id)
#1
2
You can union (or union all
, depending on what data you want) boutiques
and Boutique2
into a derived table, and then join that to boutiques_categories through boutiques_categories_categories.
您可以将精品店和精品店2联合(或联合所有,具体取决于您想要的数据)到派生表中,然后通过boutiques_categories_categories将其加入boutiques_categories。
The table data that you included in your question doesn't seem completely accurate though. Specifically: boutiques_categories_categories containing boutique_id and categorie_id values that don't match the id columns of the associated tables. I'm just going to assume that boutiques_categories_categories have int ID values. If this is not the case, please clarify in the comments, and I can adjust the query appropriately.
您在问题中包含的表格数据似乎并不完全准确。具体来说:boutiques_categories_categories包含与相关表的id列不匹配的boutique_id和categorie_id值。我只是假设boutiques_categories_categories有int ID值。如果不是这种情况,请在评论中说明,我可以适当调整查询。
Give this query a try, and see if it returns the data that you expect:
尝试使用此查询,看看它是否返回您期望的数据:
select
b.id, b.name, c.name
from
-- Get the boutiques rows from the unioned tables
(
select id, name from boutiques
union
select id, name from Boutique2
) as b
-- Join in boutiques_cateogires_categories
join boutiques_categories_categories cc
on (b.id=cc.boutique_id)
-- Join in boutiques_categories
join boutiques_categories c
on (cc.categorie_id=c.id)