How to scale the y-axis with Matplotlib? I don't want to change the y-limit, I just want to extend the physical space.
如何使用Matplotlib缩放y轴?我不想改变y限制,我只是想扩展物理空间。
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2 个解决方案
#1
Just use a larger height value when you instantiate the figure:
在实例化图形时,只需使用更大的高度值:
from pylab import *
x = linspace(0, 10*pi, 2**10)
y = sin(x)
figure(figsize=(5, 10))
plot(x, y)
show()
Where figsize=(width, height) and defaults to (8, 6). Values are in inches (the dpi keyword arg can be used to define the DPI for the figure, and there's a default value in your matplotlibrc file)
其中figsize =(width,height),默认为(8,6)。值以英寸为单位(dpi关键字arg可用于定义图的DPI,并且matplotlibrc文件中有一个默认值)
For a figure already created, I believe there is a set_size_inches(width, height) method.
对于已经创建的图形,我相信有一个set_size_inches(width,height)方法。
#2
Use the subplots_adjust function to control the abount of whitespace:
使用subplots_adjust函数来控制空格的重叠:
fig.subplots_adust(bottom=0.05, top=0.95)
There is an icon on the toolbar to do this interactively with a widget
工具栏上有一个图标,可以与窗口小部件进行交互式操作
#1
Just use a larger height value when you instantiate the figure:
在实例化图形时,只需使用更大的高度值:
from pylab import *
x = linspace(0, 10*pi, 2**10)
y = sin(x)
figure(figsize=(5, 10))
plot(x, y)
show()
Where figsize=(width, height) and defaults to (8, 6). Values are in inches (the dpi keyword arg can be used to define the DPI for the figure, and there's a default value in your matplotlibrc file)
其中figsize =(width,height),默认为(8,6)。值以英寸为单位(dpi关键字arg可用于定义图的DPI,并且matplotlibrc文件中有一个默认值)
For a figure already created, I believe there is a set_size_inches(width, height) method.
对于已经创建的图形,我相信有一个set_size_inches(width,height)方法。
#2
Use the subplots_adjust function to control the abount of whitespace:
使用subplots_adjust函数来控制空格的重叠:
fig.subplots_adust(bottom=0.05, top=0.95)
There is an icon on the toolbar to do this interactively with a widget
工具栏上有一个图标,可以与窗口小部件进行交互式操作