First I am conface that I am Newbie to php
, I am using jquery(knockout js) at client side & PHP at server side. my code.
首先,我承认我是php新手,我在客户端使用jquery(knockout js),在服务器端使用php。我的代码。
Client side: I am using knockout js(Javascript)
. to call my PHP service.
客户端:我使用的是knockout js(Javascript)。调用PHP服务。
My Code:
我的代码:
self.VMSaveEditUserMode = function () {
try {
var params = { "ClientData": [controllerVM_.ClientID(), controllerVM_.VMList[0].ClientName(), controllerVM_.VMList[0].ShortName(), controllerVM_.VMList[0].Address(), controllerVM_.VMList[0].CreatedBy(), controllerVM_.VMList[0].CityName(), controllerVM_.VMList[0].PostalCode(), controllerVM_.VMList[0].ContactEmail(), controllerVM_.VMList[0].ContactPhone(), controllerVM_.VMList[0].IsCorporate()] };
$.ajax({
type: "POST",
url: URL + "index.php/phpService/SaveClient/" + controllerVM_.TokenKey(),
data: JSON.stringify(ko.toJS(params)),
contentType: "application/json",
async: true,
dataType: 'json',
cache: false,
success: function (response) {
},
error: function (ErrorResponse) {
if (ErrorResponse.statusText == "OK") {
}
else {
alert("ErrorMsg:" + ErrorResponse.statusText);
}
}
});
}
catch (error) {
alert("Catch:" + error);
}
}
Server Side My Code, I am using this PHP code to connect with DB.
服务器端我的代码,我正在使用这个PHP代码来连接DB。
PHP Code:
PHP代码:
public function SaveClient($userToken)
{
$value = json_decode($Clientdata);
echo $value->ClientData[0];
}
*My Question *:
*我的问题*:
- I am not clear on how to POST data in PHP ? I tried with
$_POST['']
method as well as many more. - 我不清楚如何在PHP中发布数据?我尝试了$_POST["]方法以及更多的方法。
- I am using eclipse as a php framework. so, not able to debug it when i post the data.Normally mode i am able to debug my code.but not from remotely.for that i made changes on
php.ini
file also. - 我使用eclipse作为php框架。因此,当我发布数据时,无法调试它。通常情况下,我可以调试我的代码。但不是从远程。为此,我对php进行了修改。ini文件。
How to get Response of Post Data on php code ?
How to debug via remote post ?
My Request sample:
我请求示例:
suppose i use:
假设我使用:
For, data: params,
only at that time my request format is.
对于数据:params,只有在那个时候我的请求格式是。
ClientData%5B%5D=4&ClientData%5B%5D=kamlesh&ClientData%5B%5D=KAM&ClientData%5B%5D=Junagadh&ClientData%5B%5D=me&ClientData%5B%5D=SANTA+ROSA&ClientData%5B%5D=76220&ClientData%5B%5D=kamlesh.vadiyatar%40gmail.com&ClientData%5B%5D=9998305904&ClientData%5B%5D=false
For, data: JSON.stringify(ko.toJS(params)),
的数据:JSON.stringify(ko.toJS(params)),
{"ClientData":["4","kamlesh","KAM","Junagadh","me","SANTA ROSA","76220","kamlesh.vadiyatar@gmail.com","9998305904",false]}
4 个解决方案
#1
7
If I understand correctly you need to create a PHP service which is able to receive REST-like requests from client.
如果我理解正确,您需要创建一个PHP服务,该服务能够从客户端接收类似rest的请求。
In order to do thad you need to access raw POST data. In PHP its being done like this:
为了实现这个目的,您需要访问原始POST数据。在PHP中,它是这样做的:
$ClientData = file_get_contents('php://input');
You can read more about php://input
in the wrappers documentation.
您可以在wrappers文档中阅读更多关于php://的输入。
Of course from the client's side the data need to be sent using the POST method and as raw data, i.e. as a string. You can obtain a string from object using JSON.stringify()
which you already do.
当然,客户端需要使用POST方法和作为原始数据(即字符串)发送数据。您可以使用JSON.stringify()从对象中获取字符串,您已经这样做了。
If you pass an object, it will be converted to string internally by jQuery using query-string format. More on that in the jQuery documentation for $.ajax (the most importatnt options being data
and processData
).
如果您传递一个对象,它将通过jQuery使用查询字符串格式在内部转换为字符串。关于这一点,请参见jQuery文档中的$。ajax(最重要的nt选项是数据和处理数据)。
#2
3
Just pass the ajax data param as an object, don't convert it into JSON. Then in PHP use $_POST directly.
只需将ajax数据param作为对象传递,不要将其转换为JSON。然后在PHP中直接使用$_POST。
Use firebug or chrome dev tools to analyze the ajax request and see which data is sent
使用firebug或chrome开发工具分析ajax请求并查看发送了哪些数据
#3
-1
Use this simple jquery function to accomplish your task
使用这个简单的jquery函数来完成任务
$.ajax({
type: "POST",
url:"scripts/dummy.php",
data:"tbl="+table,
dataType:"json", //if you want to get back response in json
beforeSend: function()
{
},
success: function(resp)
{
},
complete: function()
{
},
error: function(e)
{
alert('Error: ' + e);
}
}); //end Ajax
#4
-1
in PHP use:
在PHP中使用:
if(isset($_POST['ClientData'])){
$client_data = $_POST['ClientData']
}
now $client_data
variable should contain the array
.
现在$client_data变量应该包含数组。
For debugging purpose you can use php's built-in print_r()
function. It's pretty handy.
为了调试目的,可以使用php的内置print_r()函数。它很方便。
here's is an example:
这里是一个例子:
//make sure it's post request
if(isset($_POST)){
//now print the array nicely
echo "<pre>";
print_r($_POST);
echo "</pre>";
}
#1
7
If I understand correctly you need to create a PHP service which is able to receive REST-like requests from client.
如果我理解正确,您需要创建一个PHP服务,该服务能够从客户端接收类似rest的请求。
In order to do thad you need to access raw POST data. In PHP its being done like this:
为了实现这个目的,您需要访问原始POST数据。在PHP中,它是这样做的:
$ClientData = file_get_contents('php://input');
You can read more about php://input
in the wrappers documentation.
您可以在wrappers文档中阅读更多关于php://的输入。
Of course from the client's side the data need to be sent using the POST method and as raw data, i.e. as a string. You can obtain a string from object using JSON.stringify()
which you already do.
当然,客户端需要使用POST方法和作为原始数据(即字符串)发送数据。您可以使用JSON.stringify()从对象中获取字符串,您已经这样做了。
If you pass an object, it will be converted to string internally by jQuery using query-string format. More on that in the jQuery documentation for $.ajax (the most importatnt options being data
and processData
).
如果您传递一个对象,它将通过jQuery使用查询字符串格式在内部转换为字符串。关于这一点,请参见jQuery文档中的$。ajax(最重要的nt选项是数据和处理数据)。
#2
3
Just pass the ajax data param as an object, don't convert it into JSON. Then in PHP use $_POST directly.
只需将ajax数据param作为对象传递,不要将其转换为JSON。然后在PHP中直接使用$_POST。
Use firebug or chrome dev tools to analyze the ajax request and see which data is sent
使用firebug或chrome开发工具分析ajax请求并查看发送了哪些数据
#3
-1
Use this simple jquery function to accomplish your task
使用这个简单的jquery函数来完成任务
$.ajax({
type: "POST",
url:"scripts/dummy.php",
data:"tbl="+table,
dataType:"json", //if you want to get back response in json
beforeSend: function()
{
},
success: function(resp)
{
},
complete: function()
{
},
error: function(e)
{
alert('Error: ' + e);
}
}); //end Ajax
#4
-1
in PHP use:
在PHP中使用:
if(isset($_POST['ClientData'])){
$client_data = $_POST['ClientData']
}
now $client_data
variable should contain the array
.
现在$client_data变量应该包含数组。
For debugging purpose you can use php's built-in print_r()
function. It's pretty handy.
为了调试目的,可以使用php的内置print_r()函数。它很方便。
here's is an example:
这里是一个例子:
//make sure it's post request
if(isset($_POST)){
//now print the array nicely
echo "<pre>";
print_r($_POST);
echo "</pre>";
}