So i've got a list with local weather details, http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl. And I want to display some of that in formation via php on my site, but can't really find out how JSON is something completely new for me.
所以我有一份当地天气详情列表,http://api.openweathermap.org/data/2.5/weather?q = Schimmert,nl。我希望在我的网站上通过php显示其中的一些信息,但无法真正了解JSON对我来说是一个全新的东西。
And the only thing i managed to do right now is this: http://jeroenonline.biz/JSON/index.php. So this is a simple script:
我现在唯一能做的就是:http://jeroenonline.biz/JSON/index.php。所以这是一个简单的脚本:
$getData = file_get_contents( "http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl");
$decode = json_decode($getData);
echo "<pre>";
print_r($decode);
3 个解决方案
#1
6
using the link
使用链接
http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl
http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl
without the "." gives me a response
没有“。”给了我一个回应
{
"message": "Error: Not found city",
"cod": "404"
}
<?php
$getData = file_get_contents( "http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl");
$decode = json_decode($getData);
// accessing it through object
echo $decode->message;
echo "<br/>";
echo $decode->cod;
// accessit via array
// set true the second parameter or the json_decode($encoded_data, TRUE)
// to give you array
$decode = json_decode($getData, TRUE);
echo "<br/>";
echo $decode['message'];
echo "<br/>";
echo $decode['cod'];
so when use the link with the "."
所以当使用带有“。”的链接时。
http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl.
http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl。
gives a response of :
给出了回复:
{
"coord": {
"lon": 5.83,
"lat": 50.91
},
"sys": {
"message": 0.0287,
"country": "Netherlands",
"sunrise": 1430884846,
"sunset": 1430939149
},
"weather": [
{
"id": 800,
"main": "Clear",
"description": "Sky is Clear",
"icon": "01n"
}
],
"base": "stations",
"main": {
"temp": 284.923,
"temp_min": 284.923,
"temp_max": 284.923,
"pressure": 1012.18,
"sea_level": 1023.56,
"grnd_level": 1012.18,
"humidity": 67
},
"wind": {
"speed": 6.06,
"deg": 219.002
},
"clouds": {
"all": 0
},
"dt": 1430875602,
"id": 0,
"name": "Nuth",
"cod": 200
}
to show the the result
显示结果
// sample to access coord
echo $decode->coord->lon;
echo $decode->coord->lat;
// sample to access sys
echo $decode->sys->message;
echo $decode->sys->country;
// sample to access weather
echo $decode->weather[0]->id;
echo $decode->weather[0]->main;
echo $decode->weather[0]->description;
// sample to access main
echo $decode->main->temp;
echo $decode->main->temp_min;
// sample to access wind
echo $decode->wind->speed;
// sample to access clouds
echo $decode->clouds->all;
echo $decode->id;
echo $decode->name;
echo $decode->cod;
#2
2
this API http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl. get some data like this
这个API http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl。得到一些像这样的数据
{
"coord": {
"lon": 5.83,
"lat": 50.91
},
"sys": {
"message": 0.039,
"country": "Netherlands",
"sunrise": 1430884846,
"sunset": 1430939149
},
"weather": [
{
"id": 800,
"main": "Clear",
"description": "Sky is Clear",
"icon": "01n"
}
],
"base": "stations",
"main": {
"temp": 284.923,
"temp_min": 284.923,
"temp_max": 284.923,
"pressure": 1012.18,
"sea_level": 1023.56,
"grnd_level": 1012.18,
"humidity": 67
},
"wind": {
"speed": 6.06,
"deg": 219.002
},
"clouds": {
"all": 0
},
"dt": 1430875157,
"id": 2749752,
"name": "Nuth",
"cod": 200
}
try this
尝试这个
<?php
$getData = file_get_contents("http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl."); // get your json data
$decode = json_decode($getData); // decode it to be an object
// echo "<pre>";
// print_r($decode);
// you can get the data with
echo "Country : " . $decode->sys->country; echo '<br>';
for($i=0;$i<count($decode->weather);$i++){
echo "ID : " . $decode->weather[0]->id; echo '<br>';
echo "Weather : " . $decode->weather[0]->main; echo '<br>';
echo "Description : " . $decode->weather[0]->description; echo '<br>';
echo "Icon : " . $decode->weather[0]->icon; echo '<br>';
}
echo "Temperature : " . $decode->main->temp; echo '<br>';
echo "Temp Min : " . $decode->main->temp_min; echo '<br>';
echo "Temp Max : " . $decode->main->temp_max; echo '<br>';
echo "Preassure : " . $decode->main->pressure; echo '<br>';
echo "Sea Level : " . $decode->main->sea_level; echo '<br>';
echo "Ground Level : " . $decode->main->grnd_level; echo '<br>';
echo "Humidity : " . $decode->main->humidity; echo '<br>';
echo "Wind Speed : " . $decode->wind->speed; echo '<br>';
echo "Wind Degrees : " . $decode->wind->deg; echo '<br>';
echo "Cloud : " . $decode->clouds->all; echo '<br>';
?>
#3
1
If you want to use the JSON as an array instead, you just have to pass true as the second paramenter for json_decode
.
如果要将JSON用作数组,则只需传递true作为json_decode的第二个参数。
$getData = file_get_contents( "http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl");
$decode = json_decode($getData, true);
echo "<pre>";
print_r($decode);
#1
6
using the link
使用链接
http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl
http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl
without the "." gives me a response
没有“。”给了我一个回应
{
"message": "Error: Not found city",
"cod": "404"
}
<?php
$getData = file_get_contents( "http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl");
$decode = json_decode($getData);
// accessing it through object
echo $decode->message;
echo "<br/>";
echo $decode->cod;
// accessit via array
// set true the second parameter or the json_decode($encoded_data, TRUE)
// to give you array
$decode = json_decode($getData, TRUE);
echo "<br/>";
echo $decode['message'];
echo "<br/>";
echo $decode['cod'];
so when use the link with the "."
所以当使用带有“。”的链接时。
http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl.
http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl。
gives a response of :
给出了回复:
{
"coord": {
"lon": 5.83,
"lat": 50.91
},
"sys": {
"message": 0.0287,
"country": "Netherlands",
"sunrise": 1430884846,
"sunset": 1430939149
},
"weather": [
{
"id": 800,
"main": "Clear",
"description": "Sky is Clear",
"icon": "01n"
}
],
"base": "stations",
"main": {
"temp": 284.923,
"temp_min": 284.923,
"temp_max": 284.923,
"pressure": 1012.18,
"sea_level": 1023.56,
"grnd_level": 1012.18,
"humidity": 67
},
"wind": {
"speed": 6.06,
"deg": 219.002
},
"clouds": {
"all": 0
},
"dt": 1430875602,
"id": 0,
"name": "Nuth",
"cod": 200
}
to show the the result
显示结果
// sample to access coord
echo $decode->coord->lon;
echo $decode->coord->lat;
// sample to access sys
echo $decode->sys->message;
echo $decode->sys->country;
// sample to access weather
echo $decode->weather[0]->id;
echo $decode->weather[0]->main;
echo $decode->weather[0]->description;
// sample to access main
echo $decode->main->temp;
echo $decode->main->temp_min;
// sample to access wind
echo $decode->wind->speed;
// sample to access clouds
echo $decode->clouds->all;
echo $decode->id;
echo $decode->name;
echo $decode->cod;
#2
2
this API http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl. get some data like this
这个API http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl。得到一些像这样的数据
{
"coord": {
"lon": 5.83,
"lat": 50.91
},
"sys": {
"message": 0.039,
"country": "Netherlands",
"sunrise": 1430884846,
"sunset": 1430939149
},
"weather": [
{
"id": 800,
"main": "Clear",
"description": "Sky is Clear",
"icon": "01n"
}
],
"base": "stations",
"main": {
"temp": 284.923,
"temp_min": 284.923,
"temp_max": 284.923,
"pressure": 1012.18,
"sea_level": 1023.56,
"grnd_level": 1012.18,
"humidity": 67
},
"wind": {
"speed": 6.06,
"deg": 219.002
},
"clouds": {
"all": 0
},
"dt": 1430875157,
"id": 2749752,
"name": "Nuth",
"cod": 200
}
try this
尝试这个
<?php
$getData = file_get_contents("http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl."); // get your json data
$decode = json_decode($getData); // decode it to be an object
// echo "<pre>";
// print_r($decode);
// you can get the data with
echo "Country : " . $decode->sys->country; echo '<br>';
for($i=0;$i<count($decode->weather);$i++){
echo "ID : " . $decode->weather[0]->id; echo '<br>';
echo "Weather : " . $decode->weather[0]->main; echo '<br>';
echo "Description : " . $decode->weather[0]->description; echo '<br>';
echo "Icon : " . $decode->weather[0]->icon; echo '<br>';
}
echo "Temperature : " . $decode->main->temp; echo '<br>';
echo "Temp Min : " . $decode->main->temp_min; echo '<br>';
echo "Temp Max : " . $decode->main->temp_max; echo '<br>';
echo "Preassure : " . $decode->main->pressure; echo '<br>';
echo "Sea Level : " . $decode->main->sea_level; echo '<br>';
echo "Ground Level : " . $decode->main->grnd_level; echo '<br>';
echo "Humidity : " . $decode->main->humidity; echo '<br>';
echo "Wind Speed : " . $decode->wind->speed; echo '<br>';
echo "Wind Degrees : " . $decode->wind->deg; echo '<br>';
echo "Cloud : " . $decode->clouds->all; echo '<br>';
?>
#3
1
If you want to use the JSON as an array instead, you just have to pass true as the second paramenter for json_decode
.
如果要将JSON用作数组,则只需传递true作为json_decode的第二个参数。
$getData = file_get_contents( "http://api.openweathermap.org/data/2.5/weather?q=Schimmert,nl");
$decode = json_decode($getData, true);
echo "<pre>";
print_r($decode);