从android调用rest api的更好方法

I am new to android programming. I am using rest call from android to query result and based on the queried result I allow user to navigate from one screen/activity to another. I have around 7 activity page and on each page I perform several operations for that I use rest call.

我是android编程的新手。我正在使用来自android的rest调用来查询结果，并根据查询结果我允许用户从一个屏幕/活动导航到另一个屏幕/活动。我有大约7个活动页面，在每个页面上我执行了几个操作，因为我使用了休息呼叫。

The way I am invoking is using AsyncHttpClient

我调用的方式是使用AsyncHttpClient

Ex.

防爆。

    AsyncHttpClient client = new AsyncHttpClient();

    client.get("http://serverurl:8080/path1/path2/path3", params, new AsyncHttpResponseHandler() {

     //some code

    }

The one problem which I am facing is if I have to modify the url I need to modify in all the activity page.

我面临的一个问题是，如果我需要修改我需要在所有活动页面中修改的URL。

Is there a way from where I can modify once that can be used in every activity? Is there a better way? Please let me know.

一旦可以在每个活动中使用，我有什么办法可以修改吗？有没有更好的办法？请告诉我。

3 个解决方案

#1

Use Retrofit

使用Retrofit

public interface GitHubService {
  @GET("users/{user}/repos")
  Call<List<Repo>> listRepos(@Path("user") String user);

  @GET("users/repos/{id}")
  Call<Repo> getRepo(@Path("id") String id);

}

Any kind of url changes can be done in this interface

可以在此界面中进行任何类型的URL更改

Initialization of retrofit with base url

用base url初始化改造

Retrofit retrofit = new Retrofit.Builder()
    .baseUrl("https://api.github.com/")
    .build();

GitHubService service = retrofit.create(GitHubService.class);

Consuming Api

消费Api

Call<List<Repo>> repos = service.listRepos("octocat");
 repos.enqueue(new Callback<List<Repo>>() {
  @Override
  public void onResponse(Call<List<Repo>> call, Response<List<Repo>> response) {
   //Do something with response 
  }

  @Override
  public void onFailure(Call<List<String>> call, Throwable t) {
    //handle failure
  }
});

For more Retrofit

更多改造

#2

There are several ways to do API calls in your android application.

在Android应用程序中有几种方法可以进行API调用。

Using a library like Retrofit, you can perform API requests without any problems by using an interface.
使用像Retrofit这样的库，您可以使用接口执行API请求而不会出现任何问题。
You can also use the default Url connection that comes with Android to do all sorts of operations like GET and POST among others.
您还可以使用Android附带的默认Url连接来执行各种操作，例如GET和POST等。

If you are worried about how to easily change the endpoint (url), you can write your code so that you pass in a string param to your methods that way, you don't hard code the value.

如果您担心如何轻松更改端点（url），则可以编写代码，以便将字符串参数传递给方法，不要对值进行硬编码。

I am sure there are a lot more libraries out there and normally, it is a matter of choice and taste.

我相信那里有更多的图书馆，通常情况下，这是一个选择和品味的问题。

I hope this helps you as you try to solve your problem!

我希望这可以帮助您解决问题！

#3

Just use a static variable.

只需使用静态变量。

public class YourClass {

    public static final String URL = "http://www.example.com/abc";

    public void performApiCall() {
        AsyncHttpClient client = new AsyncHttpClient();

        client.get(URL, params, new AsyncHttpResponseHandler() {
            //some code
        });
    }
}

You can then use the URL string from other classes:

然后，您可以使用其他类中的URL字符串：

public class SomeOtherClass {

    public void performSomeOtherApiCall() {
        AsyncHttpClient client = new AsyncHttpClient();

        client.get(YourClass.URL, params, new AsyncHttpResponseHandler() {
            //some other code
        });
    }
}

#1