从string中删除第一个和最后一个char

I have this:

我有这个：

$dataList = "*one*two*three*";
$list = explode("*", $dataList);
echo"<pre>";print_r($list);echo"</pre>";

which outputs:

哪个输出：

> Array (
>     [0] => 
>     [1] => one
>     [2] => two
>     [3] => three
>     [4] =>  )

How do I strip the fist and last * in the string before exploding?

如何在爆炸前剥去弦中的第一个和最后一个*？

4 个解决方案

#1

Using trim:

使用修剪：

trim($dataList, '*');

This will remove all * characters (even if there are more than one!) from the end and the beginning of the string.

这将从字符串的结尾和开头删除所有*字符（即使有多个！）。

#2

Some other possibilities:

其他一些可能性：

Using substr:

使用substr：

$dataList = substr($dataList, 1, -1);

You can also choose to not remove the * from the string but rather remove the empty array values which will always be the first and last element. Using array functions array_pop() and array_shift():

您也可以选择不从字符串中删除*，而是删除始终是第一个和最后一个元素的空数组值。使用数组函数array_pop（）和array_shift（）：

$arrData = array_pop(array_shift($arrData));

#3

trim($dataList, "*")

#4

echo trim($dataList,"*");

hope this solve your problem

希望这能解决你的问题

#1