摘要: 下文通过递归的方式找出最*部门的方法分享,如下所示: 实验环境:sql server 2008 R2
下文通过cte-with表达式实现递归,获取一个公司的*部门,如下所示 例:部门表
create table [maomao365.com]
(keyId int ,parentId int,
deptName nvarchar(30)) insert into [maomao365.com]
(keyId,parentId,deptName)
values
(1,0,'总经办'),
(2,0,'IT中心'),
(10,1,'销售部'),
(11,1,'售后部'),
(111,11,'售后1'),
(1111,111,'售后1_1'),
(12,1,'市场部'),
(21,2,'运维部'),
(22,2,'开发部') ---例1:获取 售后部keyId=1111所在的*部门
;
with testA( [keyId], [parentid],deptName)
as
(
select keyId, parentid,deptName
from [maomao365.com]
where keyId = 1111
union all
select a.keyId, a.parentid,a.deptName
from [maomao365.com] a
inner join testA on a.[keyId] = testA.[parentId] --递归
) select * from testA where parentId=0; go truncate table [maomao365.com]
drop table [maomao365.com]
转自:http://www.maomao365.com/?p=7829