首先新建一个实体类Person
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@Data
public class Person {
/** 编码 */
private String code;
/** 名字 */
private String name;
public Person(String code, String name) {
this .code = code;
this .name = name;
}
}
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实例化三个对象放入list集合中
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public static void main(String[] args) {
Person person1 = new Person( "001" , "张三" );
Person person2 = new Person( "002" , "李四" );
Person person3 = new Person( "002" , "王五" );
List<Person> personList = new ArrayList<>();
personList.add(person1);
personList.add(person2);
personList.add(person3);
personList.forEach(t -> System.out.println(t.toString()));
}
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输出结果为:
Person(code=001, name=张三)
Person(code=002, name=李四)
Person(code=002, name=王五)
1.抽取对象的code作为key,name作为value转化为map集合
方法为
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private static HashMap<String, String> listToMap(List<Person> personList) {
return (HashMap<String, String>)personList.stream()
.filter(t -> t.getName()!= null )
.collect(Collectors.toMap(Person::getCode,Person::getName,(k1,k2)->k2));
}
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filter() 方法作用是过滤掉名字为空的对象,当对象的名字为null时,会出现NPE空指针异常
(k1,k2)->k2 意思是遇到相同的key时取第二个值
(k1,k2)->k1 意思是遇到相同的key时取第一个值
调用这个方法
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HashMap<String,String> personMap = listToMap(personList);
personMap.forEach((k,v)-> System.out.println(k.toString() + " - " + v.toString()));
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输出结果为:
001 - 张三
002 - 王五
2.抽取对象的name得到name的list集合
方法为
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private static List<String> getNameList(List<Person> personList) {
return personList.stream().map(Person::getName).collect(Collectors.toList());
}
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调用这个方法
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List<String> nameList = getNameList(personList);
nameList.forEach(t -> System.out.println(t.toString()));
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输出结果为:
张三
李四
王五
补充:java8 使用stream将List转成Map,或者从List对象中获取单个属性List,List中根据某个字段排序
1.学生类
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import lombok.Data;
@Data
public class Student{
private String stuId;
private String name;
private String age;
private String sex;
}
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2.测试类
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public class Test {
public static void main(String[] args) {
// 创建学生List
List<Student> list = createStudentList();
// 1.获取value为Student对象,key为学生ID的Map
getStudentObjectMap(list);
// 2.获取value为学生姓名,key为学生ID的Map
getStudentNameMap(list);
// 3.获取学生姓名List
getStudentNameList(list);
//4.List中删除学生id = 1的对象
list.removeIf(student -> student.getStuId().equals( 1 ));
//5.如果StudentId为Long类型如何转?
Map<String, String> mapStr = list.stream().collect(Collectors.toMap(student -> student.getStuId().toString(), student -> JSON.toJSONString(student)));
//6.根据List中Student的学生姓名排序
Collections.sort(list, (o1, o2) -> {
if (o1.getName().compareTo(o2.getName()) > 0 ) {
return 1 ;
} else if (o1.getName().compareTo(o2.getName()) < 0 ) {
return - 1 ;
} else {
return 0 ;
}
});
//7.List遍历
List<String> listStr = new ArrayList<>();
List<Student> listStu = new ArrayList<>();
listStr.forEach(studentStr -> {
listStu.add(JSON.parseObject(studentStr, Student. class ));
});
//List根据某个字段过滤、排序
listStu.stream()
.filter(student -> student.getSex().equals( "女" ))
.sorted(Comparator.comparing(Student::getName))
.collect(Collectors.toList());
//List根据某个字段分组
Map<String,List<Student>> sexGroupMap = listStu.stream()
.collect(Collectors.groupingBy(Student::getSex));
//如果Map中多个名称相同,则studentId用逗号间隔
Map<String,String> studentNameIdMap = listStu.stream()
.collect(toMap(Student::getName,Student::getStuId,(s,a)->s+ "," +a));
}
public static List<Student> createStudentList() {
List<Student> list = new ArrayList<Student>();
Student lily = new Student();
lily.setStuId( "1" );
lily.setName( "lily" );
lily.setAge( "14" );
lily.setSex( "女" );
Student xiaoming = new Student();
xiaoming.setStuId( "2" );
xiaoming.setName( "xiaoming" );
xiaoming.setAge( "15" );
xiaoming.setSex( "男" );
list.add(lily);
list.add(xiaoming);
return list;
}
public static Map<Object, Object> getStudentObjectMap(List<Student> list) {
Map<Object, Object> map = list.stream().collect(Collectors.toMap(Student::getStuId, student -> student));
map.forEach((key, value) -> {
System.out.println( "key:" + key + ",value:" + value);
});
return map;
}
public static Map<String, String> getStudentNameMap(List<Student> list) {
Map<String, String> map = list.stream().collect(Collectors.toMap(Student::getStuId, Student::getName));
map.forEach((key, value) -> {
System.out.println( "key:" + key + ",value:" + value);
});
return map;
}
public static List<String> getStudentNameList(List<Student> list) {
List<String> result = list.stream().map(student -> student.getName()).collect(Collectors.toList());
for (String name : result) {
System.out.println( "name:" + name);
}
return result;
}
}
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以上为个人经验,希望能给大家一个参考,也希望大家多多支持服务器之家。如有错误或未考虑完全的地方,望不吝赐教。
原文链接:https://blog.csdn.net/weixin_44905182/article/details/105079266