Codeigniter 2在一个页面上形成validation_errors问题

On one of my websites I have 2 forms on one page, I am having a problem, with validation_errors(); basically what is happening, is for one of the forms I am checking for errors and if there are any errors I am doing some styling to turn the labels red, how the other form just display errors using echo validation_errors();. When I submit the form that does not display errors just error styling the validation errors are show in the form. How can I stop this?

在我的一个网站上，我在一个页面上有两个表单，我遇到了问题，有validation_errors（）;基本上发生了什么，是我检查错误的一种形式，如果有任何错误，我正在做一些样式来将标签变为红色，另一种形式如何使用echo validation_errors（）;显示错误。当我提交不显示错误的表单时，只是错误样式验证错误显示在表单中。我怎么能阻止这个？

2 个解决方案

#1

Your question is a bit hard to read, but if I understand correctly - you're having trouble validating 2 separate forms from one controller, or issues dealing with errors from different forms using validation_errors() which afaik prints ALL errors:

您的问题有点难以阅读，但如果我理解正确 - 您无法从一个控制器验证2个单独的表单，或者使用validation_errors（）处理来自不同表单的错误的问题，其中afaik打印所有错误：

Before running validation, check for the existence of either a hidden field, a field that is unique to the form, or you can check the value of the particular submit button.

在运行验证之前，请检查是否存在隐藏字段，表单唯一的字段，或者您可以检查特定提交按钮的值。

<form>
<input type="hidden" name="form1" value="whatever">
<input name="form1_email" />
<input type="submit" value="Submit Form 1" />
</form>

Then you can use any of these methods to check which form was submitted (This example checks if "form1" was submitted):

然后，您可以使用任何这些方法来检查提交的表单（此示例检查是否提交了“form1”）：

<?php
// Choose one:
if ($this->input->post('form1')): // check the hidden input
if ($this->input->post('form1_email')): // OR check a unique value
if ($this->input->post('submit') == 'Submit Form 1'): // OR check the submit button value

    if ($this->form_validation->run()):

        // process form

    else:
            // Create a variable with errors assigned to form 1
            // Make sure to pass this to your view
            $data['form1_errors'] = validation_errors();
    endif;

endif;
// Do same for form 2

Then in your view, instead of using validation_errors() you would use:

然后在您的视图中，您将使用：而不是使用validation_errors（）。

if (isset($form1_errors)) echo $form1_errors; // Print only form1's errors

If this doesn't help let me know, and clarify your question by posting your code.

如果这没有帮助，请通过发布您的代码来澄清您的问题。

#2

What I did was divide both forms. The view would be like

我所做的是划分两种形式。视图就像

    <?php echo validation_errors(); ?>
    <?php echo form_open('form1'); ?>
    <form id="form1" action="some_action">
    //Inputs
    </form> 
    <?php echo form_open('form2'); ?>
    <form id="form2" action="other_action">
    //Inputs
    </form>

Now, in the controller you can have two different functions for each validation:

现在，在控制器中，每个验证可以有两个不同的函数：

    //Controller
    function some_action(){
    //validate form and code
    } 

    function other_action(){
    //validate form2 and code
    }

Now, all validation messages will appear in the same place but will only show the messages of each form. Hope that helps

现在，所有验证消息都将出现在同一位置，但仅显示每个表单的消息。希望有所帮助

#1