Im still newbie from ajax and Jquery, I will show my data base in graphic using c3.js, but I cant use my ajax response to javascript variable. This is my JSON response from response.php
我仍然是来自ajax和Jquery的新手，我将使用c3.js在图形中显示我的数据库，但我不能使用我的ajax响应javascript变量。这是来自response.php的我的JSON响应
[{"time":"2014-05-20 17:25:00","sensor1":"25","sensor2":"20","sensor3":"31","sensor4":"33","sensor5":"27"},{"time":"2014-05-20 17:26:00","sensor1":"26","sensor2":"23","sensor3":"33","sensor4":"31","sensor5":"23"}]
and this is my response.php
这是我的回复.php
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "perkebunan";
//Connect to MySQL Server
$server = mysql_connect($dbhost, $dbuser, $dbpass);
//Select Database
mysql_select_db($dbname, $server) or die(mysql_error());
//build query
$query = "SELECT * FROM sensor";
//Execute query
$qry_result = mysql_query($query) or die(mysql_error());
$results = array();
while($row = mysql_fetch_assoc($qry_result))
{
$temp = array(
'time' => $row['time'],
'sensor1' => $row['sensor1'],
'sensor2' => $row['sensor2'],
'sensor3' => $row['sensor3'],
'sensor4' => $row['sensor4'],
'sensor5' => $row['sensor5']
);
array_push($results,$temp);
}
echo json_encode($results);
?>
and this is my database
这是我的数据库
我的数据库
so please help me to make my json response to varible in javascript. this my trial index.php to make it posible.
所以请帮助我在javascript中使我的json响应变量。这是我的试验index.php，使其成为可能的。
<html>
<head>
<!-- Load c3.css -->
<link href="c3/c3.css" rel="stylesheet" type="text/css">
<!-- Load d3.js and c3.js -->
<script src="http://d3js.org/d3.v3.min.js" charset="utf-8"></script>
<script src="c3/c3.js"></script>
<script src="jquery-2.2.3.min.js"></script>
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
</head>
<body>
<div id="chart"></div>
<script language="javascript" type="text/javascript">
function graphAjax(){
var response;
$.ajax({
type : 'POST',
url : 'ajax-example.php',
dataType : 'json',
data: { },
success: function(data){
response=data;
}
});
var chart = c3.generate({
bindto: '#chart',
data: {
json: {response
/* I hope this variable response give result like this
time: [2014-05-20 17:25:00, 2014-05-20 17:26:00, 2014-05-20 17:27:00, 2014-05-20 17:28:00, 2014-05-20 17:29:00],
sensor1: [25, 26, 27, 28, 29],
sensor2: [20, 23, 22, 25, 28],
sensor3: [31, 33, 35, 30, 33],
sensor4: [33, 31, 28, 25, 27],
sensor5: [27, 23, 21, 19, 18],
*/
}
}
});
}
</script>
<input type='button' onclick='graphAjax()' value='Start'/>
</body>
<footer>
</footer>
</html>
thank you for your time and help.
谢谢你的时间和帮助。
1 个解决方案
#1
0
Since AJAX works asyncronously you need some kind of work-around. For instance, you can move the function that generates your chart inside the success callback function (and define what happens in case of an error adding
由于AJAX异步工作，您需要某种解决方法。例如，您可以在成功回调函数中移动生成图表的函数（并定义在添加错误的情况下会发生什么
success: function(data){
response=data;
// generate chart here
},
error: function () {
// do something
},
Check also this extensive answer to How do I return the response from an asynchronous call?) or How to get the ajax response from success and assign it in a variable using jQuery?.
还要检查如何从异步调用返回响应的广泛答案？）或如何从成功中获取ajax响应并使用jQuery将其分配给变量？
#1
0
Since AJAX works asyncronously you need some kind of work-around. For instance, you can move the function that generates your chart inside the success callback function (and define what happens in case of an error adding
由于AJAX异步工作，您需要某种解决方法。例如，您可以在成功回调函数中移动生成图表的函数（并定义在添加错误的情况下会发生什么
success: function(data){
response=data;
// generate chart here
},
error: function () {
// do something
},
Check also this extensive answer to How do I return the response from an asynchronous call?) or How to get the ajax response from success and assign it in a variable using jQuery?.
还要检查如何从异步调用返回响应的广泛答案？）或如何从成功中获取ajax响应并使用jQuery将其分配给变量？