I'm learning about Jquery and I'm using JqGrid to manipulate my data. My grid fills perfectly with data from a php file 'admin_db', that "convert" its data into a xml file, like this:
我正在学习Jquery,我正在使用JqGrid来操纵我的数据。我的网格完全填充来自php文件'admin_db'的数据,将其数据“转换”为xml文件,如下所示:
//php file
while($row = mysql_fetch_array($result,MYSQL_ASSOC)) {
$s .= "<row id='". $row['id_alum']."'>";
$s .= "<cell>". $row['id_alum']."</cell>";
$s .= "<cell>". $row['name']."</cell>";
$s .= "</row>";
}
$s .= "</rows>";
echo $s;
I need to get 'id_alum' and 'name' into an array, but when I tried with this function to get data from 'name', nothing happens:
我需要将'id_alum'和'name'变成数组,但是当我尝试使用此函数从'name'获取数据时,没有任何反应:
type: "GET",
url: "admin_db.php",
dataType: "xml",
$(xml).find('name').each(function(){...}
I hope that you can help me with my problem, I really need to get my data into an array. Thank you in advance =) (Sorry if my english is bad, I'm still learning)
我希望你可以帮我解决我的问题,我真的需要把我的数据放到一个数组中。提前谢谢=)(对不起,如果我的英语不好,我还在学习)
1 个解决方案
#1
1
try using:
尝试使用:
type: "GET",
url: "admin_db.php",
dataType: "xml",
success: function(xml) {
$(xml).find('row').each(function(){
var id_alum = $(this).find('cell:eq(0)').text();
var name = $(this).find('cell:eq(1)').text();
})
}
It's just a quick one... :)
这只是一个快速的... :)
#1
1
try using:
尝试使用:
type: "GET",
url: "admin_db.php",
dataType: "xml",
success: function(xml) {
$(xml).find('row').each(function(){
var id_alum = $(this).find('cell:eq(0)').text();
var name = $(this).find('cell:eq(1)').text();
})
}
It's just a quick one... :)
这只是一个快速的... :)