file_get_contents()没有响应 - php

时间:2022-10-08 18:12:44

I am trying to call a web service which basicaly looks like this:

我试图调用一个基本上看起来像这样的Web服务:

http://10.10.10.10:8080/gw/someAction?amount=10&description='Some description'

So this is how i call this web service:

这就是我称之为Web服务的方式:

$endpoint = "http://10.10.10.10:8080/gw/someAction?amount=10&description='Some description'";

    $opts = array('http' =>
            array(
                    'method' => 'GET',
                    'header'  => 'Content-type: application/xml'
            )
    );

    $context  = stream_context_create( $opts );

    $result = file_get_contents( $endpoint, false, $context );
    $xml_result = simplexml_load_string( $result );
    echo $xml_result->success;

So here, i got nothing, the xml_result is empty. And here is the interesting part - when i remove the blank space from the description:

所以在这里,我什么都没有,xml_result是空的。这是有趣的部分 - 当我从描述中删除空格时:

 http://10.10.10.10:8080/gw/someAction?amount=10&description='Somedescription'

Everything is just fine, I got the answer from the web service. Also tried to call the web service with the chrome rest client WITH the blank space in the description and everything is OK, i have response. So this leads me to some kind of PHP problem here with the blank spaces in the web service. Please, help !

一切都很好,我从网络服务得到答案。还尝试使用chrome rest客户端调用Web服务和描述中的空白区域,一切正常,我有回复。所以这导致我在这里使用Web服务中的空格来处理某种PHP问题。请帮忙 !

UPDATE:

print_r($result)

results in

1

1 个解决方案

#1


This is not a valid URL, spaces must be escaped:

这不是有效的URL,必须转义空格:

http://10.10.10.10:8080/gw/someAction?amount=10&description='Some%20description'

You might want to take a look at How to properly URL encode a string in PHP?.

您可能想看一下如何在PHP中正确地对字符串进行URL编码?

#1


This is not a valid URL, spaces must be escaped:

这不是有效的URL,必须转义空格:

http://10.10.10.10:8080/gw/someAction?amount=10&description='Some%20description'

You might want to take a look at How to properly URL encode a string in PHP?.

您可能想看一下如何在PHP中正确地对字符串进行URL编码?