ajax调用必须从ajax.php中的方法获得响应？

This is my ajax call.

这是我的ajax电话。

   $(document).on('click','#Quote_create_value',function(){
        $.ajax({
            type : 'GET',
            url : '../../../protected/config/ajax.php',
            success : function(response){
                $("#Quote_template_value").html(response);
            }
        });
   });

I have many methods in ajax.php. Each and every method throws some response.

我在ajax.php中有很多方法。每种方法都会引发一些反应。

    <?php
      function respose()
      {
        $query = "select * from quote where template IS NOT NULL";
        $result = mysql_query($query, $con);
        while ($row = mysql_fetch_assoc($result)) {
            echo '<option value="'.$row['template'].'">' . $row['template'] . '</option>';
        }

        $query1 = "select * from template";
        $data = mysql_query($query1,$con);
        while ($row = mysql_fetch_assoc($data)) {
            echo json_encode($row);
        }
      }

      function result()
      {
      }

    ?>

But i want to get response from one method [ie. from response()].

但我想从一种方法得到回应[即。来自response()]。

How can this be done?

如何才能做到这一点?

1 个解决方案

#1

You could include a selector in the ajax request data. Like this for example:

您可以在ajax请求数据中包含一个选择器。像这样举例如:

   $(document).on('click','#Quote_create_value',function(){
        $.ajax({
            type : 'GET',
            url : '../../../protected/config/ajax.php',
            data: "function=result",
            success : function(response){
                $("#Quote_template_value").html(response);
            }
        });
   });

Then in your PHP code, a simple if-statement will check which one to output.

然后在PHP代码中,一个简单的if语句将检查输出哪一个。

if(isset($_GET['function'])) {
    if($_GET['result'] == 'result') {
        // do result stuff
    } elseif($_GET['function'] == 'response') {
        // do response stuff
    }
}

#1