In my front end JavaScript application, I make an ajax request to fetch data from the server. As soon as I get the data, I want to return that piece of information to the view.
在我的前端JavaScript应用程序中,我发出一个ajax请求来从服务器获取数据。一旦我获得数据,我想将该信息返回给视图。
var view_data;
$.ajax({
url:"/getDataFromServer.json",
//async: false,
type: "POST",
dataType: "json",
success:function(response_data_json) {
view_data = response_data_json.view_data;
console.log(view_data); //Shows the correct piece of information
return view_data; // Does not work. Returns empty data
}
});
// return view_data; --> Keeping the return outside of the ajax call works but then I need to make my ajax call synchronous in order for this return clause to be executed after the ajax call fetches data.
How would I do this?
我该怎么办?
2 个解决方案
#1
16
Instead of returning data
from success
: pass data
to a function.
而不是从成功返回数据:将数据传递给函数。
var view_data;
$.ajax({
url:"/getDataFromServer.json",
//async: false,
type: "POST",
dataType: "json",
success:function(response_data_json) {
view_data = response_data_json.view_data;
console.log(view_data); //Shows the correct piece of information
doWork(view_data); // Pass data to a function
}
});
function doWork(data)
{
//perform work here
}
#2
2
ajax is by nature asyc. The code doesn't wait for the response from your success
callback, so the data isn't accessible outside of success
unless passed.
ajax本质上是asyc。代码不会等待成功回调的响应,因此除非通过,否则无法在成功之外访问数据。
You'd need to handle the data inside the success, try calling a separate method/function:
您需要处理成功内部的数据,尝试调用单独的方法/函数:
function handleResponse(data) {
// do something with data
}
success:function(response_data_json) {
handleResponse(response_data_json.view_data);
}
here are the docs on jquery's ajax method
这里是关于jquery的ajax方法的文档
You could also just use an external success function rather then an annon inline that then calls the function anyway. it will still pass the data as a param
您也可以使用外部成功函数,而不是内联,然后调用函数。它仍然会将数据作为参数传递
function handleResponse(data) {
// do something
}
$.ajax({
url:"/getDataFromServer.json",
//async: false,
type: "GET",
dataType: "json",
success:handleResponse
});
UPDATE: as pointed out in the comments, you might be better using a http get
request rather then a post
. they both have advantages however get
requests can be cached, so for retrieving data it might give a perf boost.
更新:正如评论中所指出的,您可能更好地使用http get请求而不是帖子。它们都有优势,但是可以缓存请求,因此对于检索数据,它可能会提供性能提升。
#1
16
Instead of returning data
from success
: pass data
to a function.
而不是从成功返回数据:将数据传递给函数。
var view_data;
$.ajax({
url:"/getDataFromServer.json",
//async: false,
type: "POST",
dataType: "json",
success:function(response_data_json) {
view_data = response_data_json.view_data;
console.log(view_data); //Shows the correct piece of information
doWork(view_data); // Pass data to a function
}
});
function doWork(data)
{
//perform work here
}
#2
2
ajax is by nature asyc. The code doesn't wait for the response from your success
callback, so the data isn't accessible outside of success
unless passed.
ajax本质上是asyc。代码不会等待成功回调的响应,因此除非通过,否则无法在成功之外访问数据。
You'd need to handle the data inside the success, try calling a separate method/function:
您需要处理成功内部的数据,尝试调用单独的方法/函数:
function handleResponse(data) {
// do something with data
}
success:function(response_data_json) {
handleResponse(response_data_json.view_data);
}
here are the docs on jquery's ajax method
这里是关于jquery的ajax方法的文档
You could also just use an external success function rather then an annon inline that then calls the function anyway. it will still pass the data as a param
您也可以使用外部成功函数,而不是内联,然后调用函数。它仍然会将数据作为参数传递
function handleResponse(data) {
// do something
}
$.ajax({
url:"/getDataFromServer.json",
//async: false,
type: "GET",
dataType: "json",
success:handleResponse
});
UPDATE: as pointed out in the comments, you might be better using a http get
request rather then a post
. they both have advantages however get
requests can be cached, so for retrieving data it might give a perf boost.
更新:正如评论中所指出的,您可能更好地使用http get请求而不是帖子。它们都有优势,但是可以缓存请求,因此对于检索数据,它可能会提供性能提升。