Here I have pasted my code, I want to return the response of $.ajax as response of function a(). But before the result comes up of ajax call, it is returning the empty f. please help on this
这里我粘贴了代码,我想返回$的响应。ajax作为函数a()的响应。但是在ajax调用的结果出现之前,它返回的是空的f
a = function()
{
var f = '';
$.ajax({
url: 'http://api.twitter.com/1/statuses/user_timeline.json?screen_name=immaulikvora&count=1&page=1&include_entities=1&callback=?',
dataType: 'json',
async: false,
success: function(data) {
f = data;
}
});
return f;
};
var lid = a();
alert(lid);
3 个解决方案
#1
8
I guess you are using jQuery 1.8+
我猜你用的是jQuery 1.8+
http://api.jquery.com/jQuery.ajax/
http://api.jquery.com/jQuery.ajax/
Please read the fine print.
请阅读小字。
As of jQuery 1.8, the use of async: false with jqXHR ($.Deferred) is deprecated;
在jQuery 1.8中,使用async: false与jqXHR ($.Deferred)被弃用;
you must use the complete/success/error callbacks.
您必须使用完整/成功/错误回调。
try
试一试
http://jsfiddle.net/UgrLE/
#2
10
Please assign the ajax to jqXHR object and reading the responseText will help you.
请将ajax分配给jqXHR对象,阅读responseText将帮助您。
var jqXHR=$.ajax({
url: 'http://api.twitter.com/1/statuses/user_timeline.json?screen_name=immaulikvora&count=1&page=1&include_entities=1&callback=?',
dataType: 'json',
async: false
});
jqXHR.responseText // This will give you the result
#3
1
Unless you work for twitter, I would assume it is failing because "Cross-domain requests and dataType: "jsonp" requests do not support synchronous operation."
除非您在twitter上工作,否则我认为它失败了,因为“跨域请求和数据类型:”jsonp“请求不支持同步操作”。
Deprecated != removed and even if it did I take the deprecation is in the context of the returned jqXHR which are not being used here.
弃用!=删除,即使我使用了弃用,在返回的jqXHR的上下文中也没有使用。
http://api.jquery.com/jQuery.ajax/
http://api.jquery.com/jQuery.ajax/
It looks like @Murali provides a work-around, but the above is important to point out for those having issue with same-domain requests.
看起来@Murali提供了一种工作,但是上面的内容对于那些有相同域请求的人来说是很重要的。
#1
8
I guess you are using jQuery 1.8+
我猜你用的是jQuery 1.8+
http://api.jquery.com/jQuery.ajax/
http://api.jquery.com/jQuery.ajax/
Please read the fine print.
请阅读小字。
As of jQuery 1.8, the use of async: false with jqXHR ($.Deferred) is deprecated;
在jQuery 1.8中,使用async: false与jqXHR ($.Deferred)被弃用;
you must use the complete/success/error callbacks.
您必须使用完整/成功/错误回调。
try
试一试
http://jsfiddle.net/UgrLE/
#2
10
Please assign the ajax to jqXHR object and reading the responseText will help you.
请将ajax分配给jqXHR对象,阅读responseText将帮助您。
var jqXHR=$.ajax({
url: 'http://api.twitter.com/1/statuses/user_timeline.json?screen_name=immaulikvora&count=1&page=1&include_entities=1&callback=?',
dataType: 'json',
async: false
});
jqXHR.responseText // This will give you the result
#3
1
Unless you work for twitter, I would assume it is failing because "Cross-domain requests and dataType: "jsonp" requests do not support synchronous operation."
除非您在twitter上工作,否则我认为它失败了,因为“跨域请求和数据类型:”jsonp“请求不支持同步操作”。
Deprecated != removed and even if it did I take the deprecation is in the context of the returned jqXHR which are not being used here.
弃用!=删除,即使我使用了弃用,在返回的jqXHR的上下文中也没有使用。
http://api.jquery.com/jQuery.ajax/
http://api.jquery.com/jQuery.ajax/
It looks like @Murali provides a work-around, but the above is important to point out for those having issue with same-domain requests.
看起来@Murali提供了一种工作,但是上面的内容对于那些有相同域请求的人来说是很重要的。