Django:在模板中获取当前页的URL，包括参数

Is there a way to get the current page URL and all its parameters in a Django template?

是否有方法在Django模板中获取当前页面URL及其所有参数?

For example, a templatetag that would print a full URL like /foo/bar?param=1&baz=2

例如，一个templatetag，它将打印完整的URL，比如/foo/bar?param=1&baz=2

6 个解决方案

#1

Write a custom context processor. e.g.

编写自定义上下文处理器。如。

def get_current_path(request):
    return {
       'current_path': request.get_full_path()
     }

add a path to that function in your TEMPLATE_CONTEXT_PROCESSORS settings variable, and use it in your template like so:

在template_context_processor设置变量中为该函数添加一个路径，并在模板中使用它，如下所示:

{{ current_path }}

If you want to have the full request object in every request, you can use the built-in django.core.context_processors.request context processor, and then use {{ request.get_full_path }} in your template.

如果希望在每个请求中包含完整的request对象，可以使用内置的django.core.context_processor。请求上下文处理器，然后使用{{请求。模板中的get_full_path}。

See:

看到的:

Custom Context Processors
自定义上下文处理器
HTTPRequest's get_full_path() method.
HTTPRequest的get_full_path()方法。

#2

Use Django's build in context processor to get the request in template context. In settings add request processor to TEMPLATE_CONTEXT_PROCESSORS

使用Django在上下文处理器中的构建来获得模板上下文中的请求。在设置中，向template_context_processor添加请求处理器

TEMPLATE_CONTEXT_PROCESSORS = (

    # Put your context processors here

    'django.core.context_processors.request',
)

And in template use:

在模板中使用:

{{ request.get_full_path }}

This way you do not need to write any new code by yourself.

这样，您就不需要自己编写任何新代码。

#3

In a file context_processors.py (or the like):

在文件context_processors。py(或类似的):

def myurl( request ):
  return { 'myurlx': request.get_full_path() }

In settings.py:

在settings.py:

TEMPLATE_CONTEXT_PROCESSORS = (
  ...
  wherever_it_is.context_processors.myurl,
  ...

In your template.html:

在你template.html:

myurl={{myurlx}}

#4

Django has a lot of built-in stuff, but if you don't explicit what do you want to use, it won't be used.

Django有很多内置的东西，但是如果您不明确要使用什么，就不会使用它。

So, in MTV schema (Model, Template, View) the view receives a request and uses a template render to generate a response, passing on it a dictionary or all local variables (using the locals() function) of this view. Knowing this, we can insert the current url that came from the response, like this:

因此，在MTV模式(模型、模板、视图)中，视图接收请求并使用模板呈现来生成响应，并将该视图的字典或所有局部变量(使用local()函数)传递给它。了解了这一点，我们可以插入来自响应的当前url，如下所示:

views.py:

from django.shortcuts import render

def page(request):
    currentUrl = request.get_full_path()
    return render(request, 'app/page.html', locals())

Then, in the template 'app/page.html' you just have to do the following to display the currentUrl variable that we just created and passed through via locals():

然后，在模板的app/页面。您只需执行以下操作，以显示我们刚刚创建并通过local()传递的currentUrl变量:

app/template/page.html:

应用程序/模板/ page.html:

{{ currentUrl }}

#5

In addtition to sdolan's answer:

作为对斯多兰回答的补充:

if you are using I18N and would like to pass next value to /i18n/setlang/ to change the language of the current page, then you will need to strip off current language code from the full path either. Something like:

如果您正在使用I18N，并希望将next值传递给/ I18N /setlang/以更改当前页面的语言，那么您也需要从完整路径中删除当前语言代码。喜欢的东西:

full_path = request.get_full_path()
current_path = full_path[full_path.index('/', 1):]

This assumes that every path has format /LANG_CODE/any/other/stuff/with/?param='yay' and simply kicks off LANG_CODE whatever it is (e.g., /en/ will result into /).

这里假设每条路径都有格式/LANG_CODE/其他/其他/有/?param='yay'，并简单地启动LANG_CODE(例如，/en/将导致/)。

#6

You can see if your url differs from the others.

您可以看到您的url是否与其他url不同。

{% if 'foo/bar/' in request.get_full_path %}

#1