Django多对多内联 - 如何显示通过模型引用的字段？

I'm trying to customize and many to many inline in the django Admin, but I'm not able to display the fields of the underlying models.

我正在尝试在django Admin中自定义多个内联，但是我无法显示底层模型的字段。

Here's a simplified example. Maybe you can tell me how to reference them?

这是一个简化的例子。也许你可以告诉我如何引用它们？

Here are my models:

这是我的模特：

class Clown(models.Model):
    name = models.CharField(max_length=255)
    def edit_link(self):
        return ...

class Circus(models.Model):
    clowns = models.ManyToManyField(Clown, blank=True, through='WorkedAt')
    name = models.CharField(max_length=255)

class WorkedAt(models.Model):
    clown = models.ForeignKey(Clown)
    circus = models.ForeignKey(Circus)

and my admin:

和我的管理员：

class ClownInline(admin.TabularInline):
    model = WorkedAt
    fields = ['clown__name','clown__edit_link']


class CircusAdmin(admin.ModelAdmin):
    inlines = [
        ClownInline,
    ]
    exclude = ('clowns',)

However I get this error:

但是我收到此错误：

Unknown field(s) (clown__name) specified for WorkedAt

(I'm on Django 1.6)

（我在Django 1.6上）

Update: Why won't this work either. (Added calculated field to through model.)

更新：为什么这不起作用。（通过模型添加了计算字段。）

class Clown(models.Model):
    name = models.CharField(max_length=255)
    def edit_link(self):
        return ...

class Circus(models.Model):
    clowns = models.ManyToManyField(Clown, blank=True, through='WorkedAt')
    name = models.CharField(max_length=255)

class WorkedAt(models.Model):
    clown = models.ForeignKey(Clown)
    circus = models.ForeignKey(Circus)
    @property
    def edit_link(self):
        return self.clown.edit_link()

and my admin:

和我的管理员：

class ClownInline(admin.TabularInline):
    model = WorkedAt
    fields = ['edit_link']


class CircusAdmin(admin.ModelAdmin):
    inlines = [
        ClownInline,
    ]
    exclude = ('clowns',)

2 个解决方案

#1

Try this. Hope it solves your problem

尝试这个。希望它能解决你的问题

class ClownInline(admin.TabularInline):
    model = WorkedAt
    fields = ['clown_name', 'clown_edit_link']
    readonly_fields = ['clown_name', 'clown_edit_link']

    def clown_name(self, instance):
        return instance.clown.name
    clown_name.short_description = 'clow name'

    def clown_edit_link(self, instance):
        url = reverse("admin:%s_%s_change" % (instance.clown._meta.app_label, instance.clown._meta.module_name), args=(instance.clown.pk,))
        return '<a href="%s">%s</a>' % (url, instance.clown.name)
    clown_edit_link.allow_tags = True


class CircusAdmin(admin.ModelAdmin):
    inlines = [
        ClownInline,
    ]
    exclude = ('clowns',)

#2

I don't know if anyone still needs this, because this question is 4 years old but this solved my problem for in Django 2.0.3:

我不知道是否还有人需要这个，因为这个问题已经有4年了但是这解决了我在Django 2.0.3中遇到的问题：

# models.py
class Clown(models.Model):
    name = models.CharField(max_length=255)
    def edit_link(self):
        return ...


class Circus(models.Model):
    clowns = models.ManyToManyField(Clown, blank=True, through='WorkedAt')
    name = models.CharField(max_length=255)


class WorkedAt(models.Model):
    clown = models.ForeignKey(Clown)
    circus = models.ForeignKey(Circus)


# admin.py
class WorkedAtInline(admin.TabularInline):
    model = WorkedAt
    extra = 1


class WorkedAtAdmin(admin.ModelAdmin):
    inlines = (WorkedAtInline,)


admin.site.register(Clown, WorkedAtAdmin)

Hope this helps anyone that stumbles upon this problem and looks into this answer.

希望这有助于任何人偶然发现这个问题，并研究这个答案。

#1